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Yakvenalex [24]
3 years ago
15

What is the constant difference for a hyperbola with a foci f1 (- 8, 0) and F2 (8,0) and the point on the hyperbola (8, 30)

Mathematics
1 answer:
Ludmilka [50]3 years ago
7 0
F1P - F2P = k ;
F1P = \sqrt{ (-8-8)^{2} + (0-30)^{2} } = \sqrt{64 + 900} =  \sqrt{964} = 31.04;
F2P = \sqrt{ (8-8)^{2} + (0-30)^{2} }  =  \sqrt{900} = 30;
31.04 - 31 = 0.04 => k = 0.04 ;
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Solve system of equations 2x + 2y + 5z = 7 6x + 8y + 5z = 9 2x + 3y + 5z = 6
svet-max [94.6K]

Answer:

the values of x, y and z are x= 2, y =-1 and z=1

Step-by-step explanation:

We need to solve the following system of equations.

We will use elimination method to solve these equations and find the values of x, y and z.

2x + 2y + 5z = 7     eq(1)

6x + 8y + 5z = 9     eq(2)

2x + 3y + 5z = 6     eq(3)

Subtracting eq(1) and eq(3)

2x + 2y + 5z = 7

2x + 3y + 5z = 6

-    -       -        -

_____________

0 -y + 0 = 1

-y = 1

=> y = -1

Subtracting eq(2) and eq(3)

6x + 8y + 5z = 9    

2x + 3y + 5z = 6    

-     -      -          -

______________

4x + 5y +0z = 3    

4x + 5y = 3      eq(4)

Putting value of y = -1 in equation 4

4x + 5y = 3

4x + 5(-1) = 3

4x -5 = 3

4x = 3+5

4x = 8

x= 8/4

x = 2

Putting value of x=2 and y=-1 in eq(1)

2x + 2y + 5z = 7

2(2) + 2(-1) + 5z = 7

4 -2 + 5z = 7

2 + 5z = 7

5z = 7 -2

5z = 5

z = 5/5

z = 1

So, the values of x, y and z are x= 2, y =-1 and z=1

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Answer:

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Step-by-step explanation:

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