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1 year ago

In rectangle FGHI, diagonals FH and GI intersect at E. G F E H I • IE = 3x + 4 • EG = 5x - 6 What is the length of FH ?

Mathematics

1 answer:

timurjin [86]1 year ago

3 0

Answer:

FH = 38

Step-by-step explanation:

Here, given the point of intersection of the two diagonals at E, we want to calculate the length of FH

The point of intersection of the diagonals is the midpoint of each as the diagonals bisect each other

thus,

3x + 4 = 5x - 6

5x-3x = 6+ 4

2x = 10

x= 10/2

x = 5

but Eg is 5x-6

and FH = 2EG

FH = 2(5x-6)

FH = 10x - 12

Substitute x = 5

FH = 10(5) -12

FH = 50-12

FH = 38

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$\sqrt[4]{(16a^4)^5}=(16a^4)^{\frac{5}{4}}$ [Since, $\sqrt[n]{x}=x^{\frac{1}{n}}$ ]

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2 years ago

In rectangle FGHI, diagonals FH and GI intersect at E. G F E H I • IE = 3x + 4 • EG = 5x - 6 What is the length of FH ?​

In rectangle FGHI, diagonals FH and GI intersect at E. G F E H I • IE = 3x + 4 • EG = 5x - 6 What is the length of FH ?