Ok
so i think you would need to add around the table and then you got the answer
Answer:
x<−3
Step-by-step explanation:
Answer:
The solution to the system is
,
and
Step-by-step explanation:
Cramer's rule defines the solution of a system of equations in the following way:
,
and
where
,
and
are the determinants formed by replacing the x,y and z-column values with the answer-column values respectively.
is the determinant of the system. Let's see how this rule applies to this system.
The system can be written in matrix form like:
![\left[\begin{array}{ccc}5&-3&1\\0&2&-3\\7&10&0\end{array}\right]\times \left[\begin{array}{c}x&y&z\end{array}\right] = \left[\begin{array}{c}6&11&-13\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D5%26-3%261%5C%5C0%262%26-3%5C%5C7%2610%260%5Cend%7Barray%7D%5Cright%5D%5Ctimes%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dx%26y%26z%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D6%2611%26-13%5Cend%7Barray%7D%5Cright%5D)
Then each of the previous determinants are given by:
Notice how the x-column has been substituted with the answer-column one.
Notice how the y-column has been substituted with the answer-column one.

Then, substituting the values:



If the smaller number is n, then the next odd integer can be expressed as n+2. The sum of these is
n + n + 2
or
2n + 2

Since both y squared and 6y have a common factor of y, can put that to the side and divide both the y squared and 6y to get the second step of the work shown above. Separate both the y on the outside of the parentheses and the numbers within the parentheses and set them both equal to 0 as shown in step 3 of the work shown above. Finally solve for y as you would normally. Those two number in step 4 should be your final answer.