Samir begins riding his bike at a rate of 6 mph. Twelve minutes later, Chris leaves from the same point and bikes along the same

Question

3 years ago

13

Samir begins riding his bike at a rate of 6 mph. Twelve minutes later, Chris leaves from the same point and bikes along the same

route at 9 mph. At any given time, t, the distance traveled can be calculated using the formula d = rt, where d represents distance and r represents rate. How long after Chris begins riding does he catch up to Samir?

Mathematics

2 answers:

Pachacha [2.7K] · Answer 1 · 2021-12-06T20:24:06+03:00

Pachacha [2.7K]3 years ago

8 0

The answer would be 24 minutes

andreyandreev [35.5K] · Answer 2 · 2021-12-06T22:39:47+03:00

Answer: After 24 minutes Chris begins riding so, he catch up to Samir.

Step-by-step explanation:

Since we have given that

Speed of Samir riding his bike = 6mph

Speed of Chris riding his bike = 9 mph

Time taken by Chris be x

Time taken by Samir be x+12

AS we have given that at any given time ,t, the distance traveled can be using the formula " d=rt "

where d means distance and r represents rate.

So, our equation becomes,

$9x=6(x+12)\\\\9x=6x+72\\\\9x-6x=72\\\\3x=72\\\\x=\frac{72}{3}=24\ minutes$

As there is no need to change mph into miles per minutes as applying both will nullify the effect.

Hence, after 24 minutes Chris begins riding so, he catch up to Samir.