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3 years ago

1. If 9 students sharpen 18 pencils in 2 minutes, how many students will it take to sharpen 18 pencils in 1 minute?

1 answer:

5 0

A) If 9 students sharpen 18 pencils in 2 minutes,Then if the time is halved, it will take twice as many men to sharpen 18 pencils.Hence it will take 18 students to sharpen 18 pencils in one minute B) y & 1/x. Then y = K/x where K is our constant of proportionality.Then K = yx. When x = -64 and y = -16 then K = -64 * -16 = 1024. Option DC) When x = 3 y = 8. So for an inverse variation K as calculated from B = 3 * 8 = 24.Then when K = 24 and y = 6; we have 24 = 6x. Hence x = 4. Option A

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G(a) = 3^3a-2 . Find g(1)

OleMash [197]

Sub 1 for a

$G(1)=3^{3(1)-2}$
$G(1)=3^{3-2}$
$G(1)=3^{1}$
$G(1)=3$

5 0

3 years ago

IF TWO ANGLES ARE CONSECUTIVE EXTERIOR ANGLES AND <1=59, WHAT IS THE MEASURE OF <2?

lutik1710 [3]

Answer:

<2 = 121

Step-by-step explanation:

Consecutive exterior angles add up to 180 degrees.

6 0

3 years ago

What is the formula for a confidence interval?

ikadub [295]

Answer:

a) The formula is given by mean $\pm$ the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.

b) $\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

If the distribution for X is normal or if the sample size is large enough we know that the distribution for the sample mean $\bar X$ is given by:

$\bar X \sim N(\mu, \frac{\sigma}{\sqrt{n}})$

Part a

The formula is given by mean $\pm$ the margin of error. Where the margin of error is the product between the critical value from the normal standard distribution at the confidence level selected and the standard deviation for the sample mean.

Part b

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$

5 0

3 years ago

How would you estimate it?

likoan [24]

I would just do for the first one 7/16 - 3/16 = 4/16 which is also 1/4 I'm not sure ho2 you estimate it

7 0

3 years ago

3w + 6(w – 4) = 156, what does w equal?

RSB [31]

<h2>3w + 6 (w - 4) = 156</h2><h2 /><h2>3w + 6w - 24 = 156</h2><h2 /><h2>9w - 24 = 156</h2><h2 /><h2>9w = 180</h2><h2>÷9 ÷9 ← divide by 9 on both sides</h2><h2 /><h2> w = 20</h2>

3 0

3 years ago