All categories

3 years ago

Which shows a reflection of the triangle?

Mathematics

2 answers:

Rudik [331]3 years ago

7 0

C , the last one is the reflection of the triangle .

lora16 [44]3 years ago

4 0

C, or the last photo, shows a reflection.

You might be interested in

lenny deposits $7,000 in an IRA. What will be the value of his investment in 3 years if the investment is earning 1.95% per year

lorasvet [3.4K]

Step-by-step explanation:

The interest is 1.95 percent.

1.95 percent = 1.0195

Value after 3 years =

$1.0195 {}^{3} \times 7000$

= $7417.54 (to the nearest cent)

4 0

3 years ago

Read 2 more answers

I have a test tomorrow, I don't get how my teacher got 3 2/3 not this problem. If you answer, please show your work, so I can se

gogolik [260]

Which problem ,???????

3 0

3 years ago

Read 2 more answers

Find the 5th term of the sequence in which T1=8 and Tn=3t n-1

yan [13]

T_n = 3 * T_(n-1)

Long way (always works!)
T_5 = 3*T_4,
T_4 = 3*T_3
T_3 = 3*T_2
T_2 = 3*T_1

T_5 = 3*3*3*3*T_1 = 81*T_1 = 81*8 = 648!

Short way (sometimes it works!)

T_n = 3^(n-1) * T_1 (this case is a geometric series of ratio-=3)
T_5 = 3^4*8 = 648

6 0

3 years ago

Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro

Elanso [62]

Answer:

<em>Choose the first alternative</em>

$\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}$

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions $(N_s)$ and the total number of possible choices $(N_t)$ , i.e.

$\displaystyle P=\frac{N_s}{N_t}$

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

$_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}$

The total number of possible choices is

$_{2}^{20}\textrm{C} \text{ ways to do it}$

The probability is then

$\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}$

Choose the first alternative

7 0

3 years ago

Read 2 more answers

The graph of a proportional relationship contains the point (8, 4).

Softa [21]

$\bf \qquad \qquad \textit{direct proportional variation}\\\\
\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad y=kx\impliedby 
\begin{array}{llll}
k=constant\ of\\
\qquad variation
\end{array}\\\\
-------------------------------\\\\
(\stackrel{x}{8}~~,~~\stackrel{y}{4})\implies 
\begin{cases}
x=8\\
y=4
\end{cases}\implies 4=k8\implies \cfrac{4}{8}=k\implies \cfrac{1}{2}=k
\\\\\\
\boxed{y=\cfrac{1}{2}x}$

6 0

3 years ago