Find the area A of triangle JKL with the vertices J(5,8), K(0,7), and L(5,4)

Find the value of x in each case: PU ∩ RT = S, Q ∈ PR

Eddi Din [679]

Answer:

x=34

Step-by-step explanation:

When we look triangle SQR, we have angles 3x and 68, we know that sum angles of triangle is 180.

<R=180-(3x+68)

Now, we look at the PQS:

<PQS=180-68=112°

Then :

<PSQ=180-(112+x)=68-x

Then we have :

Angles PSR= 68-x+3x=68+2x and angles TSU=4x.

We have that

PSR=TSU

68+2x=4x

4x-2x=68

2x=68

x=34

3 0

3 years ago

On Monday Sophie ran 4 5/6 laps of a running track and on Tuesday she ran 5 3/4

MatroZZZ [7]

Answer:

10 7/12

hope this is right

Step-by-step explanation:

4 5/6 = 29/6 as an improper fraction

5 3/4 = 23/4 as an improper fraction

you times the two denominators together = 24

you times 29 by 4 = 116

you times 23 by 6 = 138

you add 116 and 138 = 254

you put this over 24 = 254/24

simplify this = 127/12

you make this a mixed number = 10 7/12

the answer is 10 7/12

3 0

3 years ago

A small business has 15 full-time employees. How many people does the small business employ if the full-time workers make up 30%

Alexxx [7]

Answer:

50 employees

Step-by-step explanation:

The total number of employees the business has will have to be made up the full-time employees and part-time employees.

The number of full-time employees = 15

Let the total number of employees = x

$15 = 30 percent of x$

$15 = 30/100 \times x\\x=1500/30 = 50$

The company has a total of 50 employees

6 0

3 years ago

Determine tan(t) if cos(t)= -3/5 and sin(t) >0

kupik [55]

$\bf cos(\theta)=\cfrac{adjacent}{hypotenuse}
\qquad 
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}\\\\
-------------------------------\\\\
cos(t)=-\cfrac{\stackrel{adjacent}{3}}{\stackrel{hypotenuse}{5}}$

now, the hypotenuse is just a radius unit, so, is never negative, so, the fraction is negative because the numerator is negative, that is, the adjacent side is -3.

now, let's use the pythagorean theorem to find the opposite side.

$\bf \textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-a^2}=b\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{5^2-(-3)^2}=b\implies \pm\sqrt{25-9}=b\implies \pm 4=b$

ok... so, which is it? the +/-? well, we also know that sin(t) >0, namely that the sine of the angle is positive, so, then is +4 then.

 $\bf tan(\theta)=\cfrac{opposite}{adjacent}\qquad \qquad tan(t)=\cfrac{4}{-3}\implies \boxed{tan(t)=-\cfrac{4}{3}}$

4 0

3 years ago

Write an expression equivalent to 6 − 2 + 5 + 4 that only has two terms. PLS HELP

olganol [36]

Answer:

15 - 2

Step-by-step explanation:

hope this helps :)

4 0

3 years ago

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