Answer:
See explanation
Step-by-step explanation:
Car A: Started at 0 and ended at 300, thus, car A travels 300 miles.
It travels 6 hours, so car A speed is 
mph.
Car B: Started at 100 and ended at 300, thus, car B travels 300-100=200 miles.
It travels 5 hours, so car B speed is 
mph.
Since 50>40, car A traveled faster than car B.
The graph for the car A is steeper than the graph for the car B.
Company A : C = 35D + 15....C is total cost and D is number of days
company B : C = 42D + 10...C is total cost and D is number of days
================
which company charges less for renting for 6 days
company A :
C = 35(6) + 15 = 225
company B :
C = 42(6) + 10 = 262
so company A charges less when renting for 6 days
=================
for 10 days...
company A :
C = 35(10) + 15 = 365
company B :
C = 42(10) + 10 = 430
so there would be (430 - 365) = 65 saved when using company A instead of company B
Represent the number of days by x. With this representation, the variable cost of the rental is 31.67x. The total cost is the sum of the fixed and variable costs. This value should not be more than $500. The equation below shows the relationship.
130 + 31.67x ≤ 500
Solving for x gives x ≤ 11.68
Thus, the maximum number of days to rent the car is only 11 days.
