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3 years ago

What is the answer???

Mathematics

2 answers:

Andrews [41]3 years ago

7 0

Answer:

you plug in the number that x is into the formula then solve it from the formula

Step-by-step explanation:

frozen [14]3 years ago

6 0

Plug in the number that x is

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Catherine ran 1/2 of a mile yesterday.

mixas84 [53]

Answer:

3.5

Step-by-step explanation:

5 0

4 years ago

Read 2 more answers

Can someone help me?

horsena [70]

The answer is 16. ....

7 0

3 years ago

What is the greatest common factor that could be used to reduce 36/90

saw5 [17]

Answer:

Step-by-step explanation:

The gcf is 18

36 divided by 18 is 2

90 divided by 18 is 5

The simplified fraction is 2/5 btw

7 0

3 years ago

Mr. Timmons wanted to fence in his rectangular back yard so that his son could play soccer. He bought 180 feet of fencing, which

elixir [45]

Answer:

The length of the yard is 60 feet while the width is 30 feet.

Step-by-step explanation:

If the length of Mr. Timmon's backyard is double the width, then the dimensions are related by the following expression:

length = 2*width

We also know the perimetter, since he has the exact length of fence to surround his whole yard, which is 180 feet. The perimeter of a rectangle is given by:

perimeter = 2*length + 2*width

Therefore,

180 = 2*length + 2*width

With the length being double the width, we have:

180 = 2*(2*width) + 2*width

180 = 4*width + 2*width

6*width = 180

width = 180/6 = 30

length = 2*width = 2*30 = 60

The length of the yard is 60 feet while the width is 30 feet.

5 0

4 years ago

Identify the x-intercepts of the function below f(x)=x^2+12x+24

damaskus [11]

<u>ANSWER: </u>

x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

<u>SOLUTION:</u>

Given, $f(x)=x^{2}+12 x+24$ -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

$X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here, for (1) a = 1, b= 12 and c = 24

$X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}$

$\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}$

Hence the x-intercepts of $\mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})$

8 0

3 years ago