Answer:
1. 0.0417
2. 0.1375
3. no
Step-by-step explanation:
lets define:
A as the probability that a car needs a warranty repair.
B as probability taht the car is manufactured by a company that is based in country X
we have the
prob(A) = 0.08
prob(B) = 0.60
prob(A∩B) = 0.025
a. we are to calculate the probability taht a car manufactured in country X needs a warranty repair.
= p(AIB) =
![P(\frac{AnB}{p(B)}) \\](https://tex.z-dn.net/?f=P%28%5Cfrac%7BAnB%7D%7Bp%28B%29%7D%29%20%5C%5C)
= 0.025/0.60
= 0.0417
2. Probability that car needs warranty repair given it was not manufactured in country X.
P(AIB')
= p(A∩B')/P(B')
= 0.08-0.025/1-0.60
= 0.055/0.40
= 0.1375
3. no, Need for warranty repair and location are not independent
Answer:
80km/h
Step-by-step explanation:
Answer:
It might be 4 pounds?
Step-by-step explanation:
7-3= 4
but this might be wrong
Answer:
No
Step-by-step explanation:
it would 12:60
6x2=12
6x10=60