Pemdas
mutliply first
5*5=25
now we have
25+9+2+2-4+6-2-3
34+2+2-4+6-2-3
36+2-4+6-2-3
38-4+6-2-3
34+6-2-3
40-2-3
38-3
35
Remark
The proof is only true if m and n are equal. Make it more general.
m = 2k
n = 2v
m + n = 2k + 2v = 2(k + v).
k and v can be equal but many times they are not. From that simple equation you cannot do anything for sure but divide by 2.
There are 4 combinations
m is divisible by 4 and n is not. The result will not be divisible by 4.
m is not divisible by 4 but n is. The result will not be divisible by 4.
But are divisible by 4 then the sum will be as well. Here's the really odd result
If both are even and not divisible by 4 then their sum is divisible by 4
Answer: 
<u>Find Common Denominator</u>
2: 2,4,6,8,10
4: 4,8,12,16,20
CD=4
<u>Add</u>
1/4+2/4=3/4
3/4=.75
By drawing?
If so, here: first outline the current shape as big as you want it... Then, erase the first shape!
