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Softa [21]
3 years ago
14

A basketball has a radius of 9 inches. What is the exact value of the volume of the ball? 64π in3 256π in3 972π in3 1024π in3

Biology
1 answer:
Tpy6a [65]3 years ago
3 0

Answer: 64 pi

Explanation: Just use a calculator

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If a neurotransmitter attaches to a ligand-gated channel and creates a potential that causes the inside of the excitable cell me
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Answer:

If a neurotransmitter attaches to a ligand-gated channel and creates a potential that causes the inside of the excitable cell membrane to become less negative, and this potential travels only a short distance before dying out, it is considered to be a <u>Graded or local potential</u>

Explanation:

<em>Graded potentials, also known as local or generator, are generated by an excitatory neurotranmitter, usually a ligan gated channel</em>, they occur at a localized place on the cell and their potentials are smaller (from 1-50mV) and its magnitude depends on the strength of the stimulus.

I hope you find this information useful and interesting! Good luck!

5 0
3 years ago
What type of response involves an organism moving to or from the earth? Geotropism, internal response, phototropism fight or fli
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Were is the choices.

6 0
3 years ago
Two solutions will be prepared with the mixture of distilled water and stock solution of KMnO4 (10 mM). Give the correct volumes
Yanka [14]

Answer:

See the answer below

Explanation:

<em>Recall that the law of dilution states that the number of moles before dilution must be equal to the number of moles after dilution.</em>

Mathematically,

     molarity x number of moles before dilution = molarity x number of moles after dilution.

For solution A: final molarity = 3 mM, final volume = 2mL, initial molarity of KMnO4 = 10 mM

Applying the equation:

    10 x initial volume = 3 x 2

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<u>Hence, Tube A should be made with 0.6 mL of 10 mM KMnO4 stock and  1.4 mL of distilled water to give a solution of 2 mL 3 mM KMnO4.</u>

For solution B:final molarity = 8 mM, final volume = 2 mL, initial molarity = 10 mM

    10 x initial volume = 8 x 2

       initial volume = 16/10 = 1.6

<u>Hence, Tube B should be made with 1.6 mL of 10 mM KMnO4 stock and 0.4 mL of distilled water to give a solution of 2 mL 8mM KMnO4. </u>

7 0
3 years ago
What would be the expected frequency of dewlap extensions and pushups in males while in the presence of females and a predator v
svp [43]

Answer:

Explanation:

Lower frequency for both dewlap extension and pushups. In the presence of predators and females an increase in the dewlap frequency and pushups is expected as a result of defense and breeding mechanisms mixed while in the second situation we have just breeding mechanisms involved

6 0
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