Well area of a rectangle is given by the equation
a = L x W
Since they give us the expression for length and width we can find the expression for the area...
a = (3x - 4) x (2x - 5) or simply
a = (3x -4)(2x - 5)
Now we multiply
6x^2 - 15x - 8x + 20 =
6x^2 - 23x + 20
Your answer is C.
If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
A) sum 3 + 7 =10
b) divide <span> £</span>300 ÷ 10 = <span> £</span>30
c) multiply:
3 x 30 = <span> £</span>90
7 x 30 = <span> £</span>210
Values are: £90 and <span> £210</span>
I only did the first part but maybe later I will solve the rest too. If there are any errors but tell me so I can update the pic.
Y - x = 6
y + 2x = 57
2y - 2x =12
y + 2x = 57
∴3y = 69
y = 23
23 - x = 6
-x = -17
x =17
large van = 23
small van = 17
