Answer:
Both fireworks will explode after 1 seconds after firework b launches.
Step-by-step explanation:
Given:
Speed of fire work A= 300 ft/s
Speed of Firework B=240 ft/s
Time before which fire work b is launched =0.25s
To Find:
How many seconds after firework b launches will both fireworks explode=?
Solution:
Let t be the time(seconds) after which both the fireworks explode.
By the time the firework a has been launched, Firework B has been launch 0.25 s, So we can treat them as two separate equation
Firework A= 330(t)
Firework B=240(t)+240(0.25)
Since we need to know the same time after which they explode, we can equate both the equations
330(t) = 240(t)+240(0.25)
300(t)= 240(t)+60
300(t)-240(t)= 60
60(t)=60
t=1
Second answer
Step-by-step explanation:
Answer:
a and d
Step-by-step explanation:
v and w are parallel lines
R is the transversal
Alternate exterior means on the opposite sides of the transversal and outside of the parallel linea
a and d are alternate exterior angles
Decay rate for Radium-228 is 0.01205
Step-by-step explanation:
The half life of radium-228 is 5.75 years. We need to find the decay rate for radium.
The formula used is:
Where N₀ = amount of radioactive particles at time = 0
N_t = amount of radioactive particles are time (t)
λ = rate of decay constant
t = time
We are given half life so, 
=0.5
t= 5.75 years
We need to find λ
Putting values in formula and solving:
So, Decay rate for Radium-228 is 0.01205.
Keywords: Decay Rate
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