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Phantasy [73]
3 years ago
6

6)532 with a remainder

Mathematics
1 answer:
BartSMP [9]3 years ago
3 0
Hello Rebelkid2004, 532 with a remainder is, gives remainder 0 and so are divisible by 1, we get factors of 532 numbers by finding numbers that can divide 532 without remainder or alternatively numbers that can multiply together to equal the target number being converted.
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Which is equivalent to 5(a + 6)?<br><br> 1. a+30<br><br> 2. 5a-30<br><br> 3. 5a+6<br><br> 4. 5a+30
Afina-wow [57]

Answer:  the answer is number four.

Step-by-step explanation:

<h2>because when you take five multiply by A (5*a) you will get 5a and when you take five multiply by six (5*6) you will get 30 and there is positive sign so the plus (+) stays the same and your will be (5a+30) that is your answer. good luck.</h2>
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3 years ago
The ratio of students to teachers at a school is 19:1 how many students are there in each total of people?
Valentin [98]

Answer:

D

Step-by-step explanation:

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3 0
2 years ago
Read 2 more answers
Heights of men have a bell-shaped distribution, with a mean of 176 cm and a standard deviation of 7 cm. Using the Empirical Rule
Vaselesa [24]

Answer:

a) 68% of the men fall between 169 cm and 183 cm of height.

b) 95% of the men will fall between 162 cm and 190 cm.

c) It is unusual for a man to be more than 197 cm tall.

Step-by-step explanation:

The 68-95-99.5 empirical rule can be used to solve this problem.

This values correspond to the percentage of data that falls within in a band around the mean with two, four and six standard deviations of width.

<em>a) What is the approximate percentage of men between 169 and 183 cm? </em>

To calculate this in an empirical way, we compare the values of this interval with the mean and the standard deviation and can be seen that this interval is one-standard deviation around the mean:

\mu-\sigma=176-7=169\\\mu+\sigma=176+7=183

Empirically, for bell-shaped distributions and approximately normal, it can be said that 68% of the men fall between 169 cm and 183 cm of height.

<em>b) Between which 2 heights would 95% of men fall?</em>

This corresponds to ±2 standard deviations off the mean.

\mu-2\sigma=176-2*7=162\\\\\mu+2\sigma=176+2*7=190

95% of the men will fall between 162 cm and 190 cm.

<em>c) Is it unusual for a man to be more than 197 cm tall?</em>

The number of standard deviations of distance from the mean is

n=(197-176)/7=3

The percentage that lies outside 3 sigmas is 0.5%, so only 0.25% is expected to be 197 cm.

It can be said that is unusual for a man to be more than 197 cm tall.

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3 years ago
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Katyanochek1 [597]
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= 3-16

= -13

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2 years ago
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