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anzhelika [568]
3 years ago
10

A popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags

have an average weight of 1,040 grams with a standard deviation of 25 grams. 1.) Fill out the normal distribution curve for this situation. 2.) What percentage of people would receive a bag that had a weight greater than 1115 grams?
Mathematics
1 answer:
ELEN [110]3 years ago
8 0

Answer:

Step-by-step explanation:

Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.

i.e. Sample mean = 1040 and

Sample std dev s = 25 gm

Sample size n = 100

Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm

\bar X = N(1040,25)

Normal curve would be with mean 1040 and std deviatin 25

b) P(X>1115)

= 1-0.9987

=0.0013

i.e. 0.13% would receive a bag that had a weight greater than 1115 grams

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bija089 [108]

Answer:

El ancho de la superficie = 444,44 my el largo = 200 m

La superficie de la superficie de la presa = 88888,89 m²

Step-by-step explanation:

Los parámetros dados son;

La altura del agua en la presa = 225 m

El volumen de agua en la presa, d = 20 millones de m³

La longitud de la base = 200 m

Sea el ancho de la presa = x

El volumen viene dado por la relación;

200 × 225 × x = 20 millones de m³

x = 20.000.000 / (200 × 225) = 444,44 m

Por tanto, las dimensiones de la superficie son ancho = 444,44 my largo = 200 m

El área de superficie de la superficie de la presa = 444.44 × 200 = 88888.89 m².

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jek_recluse [69]
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Answer:

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Step-by-step explanation:

2x^2 + 3xy - 4y^2  

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