Answer:
Incomplete question, but the concepts of the uniform distribution needed to solve this question are given here.
Step-by-step explanation:
Uniform probability distribution:
An uniform distribution has two bounds, a and b.
The probability of finding a value of at lower than x is:
![P(X < x) = \frac{x - a}{b - a}](https://tex.z-dn.net/?f=P%28X%20%3C%20x%29%20%3D%20%5Cfrac%7Bx%20-%20a%7D%7Bb%20-%20a%7D)
The probability of finding a value between c and d is:
![P(c \leq X \leq d) = \frac{d - c}{b - a}](https://tex.z-dn.net/?f=P%28c%20%5Cleq%20X%20%5Cleq%20d%29%20%3D%20%5Cfrac%7Bd%20-%20c%7D%7Bb%20-%20a%7D)
The probability of finding a value above x is:
![P(X > x) = \frac{b - x}{b - a}](https://tex.z-dn.net/?f=P%28X%20%3E%20x%29%20%3D%20%5Cfrac%7Bb%20-%20x%7D%7Bb%20-%20a%7D)
The waiting times between a subway departure schedule and the arrival of a passenger are uniformly distributed between a and b minutes.
From here, we get the values of a(smallest value) and b(highest value).
Question of the probabilities:
In the two probability questions, you will get the value of x, and will apply one of the three formulas given above, depending on the question, to find the desired probability.