Since the quadratic formula of ax^2+bx+c is
x=(-b+-(plus OR minus) sqrt (b^2-4ac))/2a, we can get that a is 1 (since 1*x^2 is x^2), b is 4, and c is -16, so x=(-4+-sqrt((-4)^2-4*1*(-16)))/2*1
= (-4+-sqrt(16-(-64)))/2=(-4+-sqrt(80))/2 which is either (-4+sqrt(80))/2 or
(-4-sqrt(80))/2. Since 80 is divisible by 4 (aka 2 squared), we can write sqrt(80) as 2*sqrt(20) as 4 goes into 80 20 times, getting (-4+2sqrt(20))/2 or
(4-2sqrt(20))/2, and crossing out the 2's we get (-2+sqrt(20)) or (-2-sqrt(20))
Answer:
.
Step-by-step explanation:
Since vertices lie on y-axis. So, it is a vertical parabola of the form
where, (h,k) is center, is focus and is vertex.
Center is (0,0). So, h=0 and k=0.
Foci are . So .
Vertices are . So .
We know that,
Put h=0,k=0, a=8 and b=3 in equation (1).
Therefore, the required equation is
.
Answer:
No solution exists
Step-by-step explanation:
<span><span><span>2x</span>−1</span>≤<span>x5
</span></span>Let's find the critical points of the inequality.
<span><span><span>2x</span>−1</span>=<span>x^5
</span></span><span><span><span><span>2x</span>−1</span>−<span>x^5</span></span>=<span><span>x^5</span>−<span>x^5 </span></span></span>(Subtract x^5 from both sides)
<span><span><span><span>−<span>x^5</span></span>+<span>2x</span></span>−1</span>=0
</span><span><span><span>(<span><span>−x</span>+1</span>)</span><span>(<span><span><span><span><span>x^4</span>+<span>x^3</span></span>+<span>x^2</span></span>+x</span>−1</span>)</span></span>=0 </span>(Factor left side of equation)
<span><span><span><span>−x</span>+1</span>=<span><span><span><span><span><span>0<span> or </span></span><span>x^4</span></span>+<span>x^3</span></span>+<span>x^2</span></span>+x</span>−1</span></span>=0 </span>(Set factors equal to 0)
<span><span><span>x=<span><span>1<span> or </span></span>x</span></span>=<span><span>0.51879<span> or </span></span>x</span></span>=<span>−<span>1.290649</span></span></span>
Answer:
<em>Question 4: letter c </em>
<em>Question 3: letter c</em>
<em />
Step-by-step explanation: