3 years ago

When x = 3 and y = 5, by how much does the value of 3x^2 – 2y exceed the value of 2x^2 – 3y ?

1 answer:

7 0

$3\cdot3^2-2\cdot5-(2\cdot3^2-3\cdot5)=27-10-(18-15)=17-3=14$

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