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Sergio039 [100]
3 years ago
13

EASY MATH (no links or get reported)

Mathematics
1 answer:
katovenus [111]3 years ago
4 0

Answer:

Find the Roots (Zeros) f(x)=x^3-6x^2+13x-20. f(x)=x3−6x2+13x−20 f ( x ) = x 3 - 6 x 2 + 13 x - 20. Set x3−6x2+13x−20 x 3 - 6 x 2 + 13 x - 20 equal to 0 0 .

Step-by-step explanation:

hope this helps

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Rewrite the expression 8×4×−2×3+8÷2 with parentheses to make this statement true: 8×4×−2×3+8÷2 = 25.
Margarita [4]

Answer:

Which statements are true about the figure? Select two options.

Line JM intersects line GK at point N.

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A cylinder has a radius of 5cm and a height of 9cm find its total area
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7 0
3 years ago
Can someone help me? It's urgent and thank you!
Irina-Kira [14]

Answer:

option A

Step-by-step explanation:

\frac{x+ 3}{12x} \ \cdot \ \frac{4x}{x^2 +x - 6}\\\\= \frac{x+ 3}{12x} \ \cdot\ \frac{4x}{x^2 +3x - 2x - 6}\\\\= \frac{x+ 3}{12x} \cdot \frac{4x}{x(x + 3) -2(x+3)}\\\\= \frac{x+ 3}{12x} \cdot \frac{4x}{(x + 3)(x -2)}\\\\= \frac{1}{12x} \ \cdot \ \frac{4x}{(x - 2)} \ \ \ \ \  \ \ \ \ \ \ \ \ \ \ \ \ \  \\\\= \frac{1}{3} \ \cdot \ \frac{1}{(x - 2)}\\\\= \frac{1}{3(x - 2) }

5 0
3 years ago
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