Answer:
asexual reproduction
Explanation:
it starts off with a single nucleus and ends up with 2, there is no obvious chromosomes or spindle fibres to suggest meiosis or mitosis
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Answer:
F (pp) = 0.04
F (Pp) = 0.32
F (PP) = 0.64
Explanation:
Studying population genetics, we used the Hardy-Weinberg equilibrium model. In the case of snails, the H-W principle predicts that the total number of cases in the population should follow the following equation: PP + 2.Pp + pp = 200.
If a population has 200 snails and 8 are affected by a recessive condition, we have 4% affected, or 0.04.
This means that 0.04 corresponds to p², and p corresponds to 0.2.
Therefore, P is equal to 0.8 because p + P = 1.
Knowing the allele frequencies, we go to the frequency of the genotypes.
F (pp) = p² = 0.04 = 8 snails
F (Pp) = 2.Pp = 0.32 = 64 snails
F (PP) = P² = 0.64 = 128 snails
The four groups of pathogenic E.coli are enteropathogenic, enterotoxigenic, verocytotoxigenic and enteroinvasive groups. These groups can best be isolated and recoved through luria broth.
<h3>What is Escherichia coli?</h3>
The pathogenic E. coli or Escherichia coli serotypes are grouped on the basis of their mechanism of causing symptoms in humans. The six groups of pathogenic E.coli are enteropathogenic, enterotoxigenic, verocytotoxigenic, enteroinvasive, enteroaggregative and diffusely adherent E. coli.
Luria broth (LB) is one of the most commonly used growth medium for E. coli. It promotes fast growth of the organism and also provides good plasmid yields, making it an excellent choice for most laboratory applications, especially the small-scale plasmid preps.
Learn more about E.coli here:
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