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3 years ago

A sphere and a cylinder have the same radius and height. The volume of the cylinder is 64m. What is the volume of the sphere

Mathematics

1 answer:

Drupady [299]3 years ago

7 0

Check the picture below.

$\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h~~
\begin{cases}
h=2r\\
V=64
\end{cases}\implies 64=\pi r^2(2r)\implies 64=3\pi r^3\implies \boxed{\cfrac{64}{3\pi }=r^3}\\\\
-------------------------------\\\\
\textit{volume of a sphere}\\\\
V=\cfrac{4\pi r^3}{3}\qquad \qquad \implies V=\cfrac{4\pi \left( \boxed{\frac{64}{3\pi }} \right)}{3}\implies V=\cfrac{256}{9}$

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2 years ago

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2 years ago

Read 2 more answers

Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that

Maksim231197 [3]

Complete Question

The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?

Answer:

The value is $P(x_1 + x_2 \ge 2 )= 0.5940$

Step-by-step explanation:

From the question we are told that

The rate at which fire breaks out every 10 years is $\lambda = 1$

Generally the probability distribution function for Poisson distribution is mathematically represented as

$P(x) = \frac{\lambda^x}{ k! } * e^{-\lambda}$

Here x represent the number of state which is 2 i.e $x_1 \ \ and \ \ x_2$

Generally the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as

$P(x_1 + x_2 \ge 2 ) = 1 - P(x_1 + x_2 \le 1 )$

=> $P(x_1 + x_2 \ge 2 ) = 1 - [P(x_1 + x_2 = 0 ) + P( x_1 + x_2 = 1 )]$

=> $P(x_1 + x_2 \ge 2 ) = 1 - [ P(x_1 = 0 , x_2 = 0 ) + P( x_1 = 0 , x_2 = 1 ) + P(x_1 , x_2 = 0)]$

=> $P(x_1 + x_2 \ge 2 ) = 1 - P(x_1 = 0)P(x_2 = 0 ) + P( x_1 = 0 ) P( x_2 = 1 )+ P(x_1 = 1 )P(x_2 = 0)$

=> $P(x_1 + x_2 \ge 2 ) = 1 - \{ [ \frac{1^0}{ 0! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]] )+ ( [ \frac{1^1}{1! } * e^{-1}] * [[ \frac{1^1}{ 1! } * e^{-1}]] ) + ( [ \frac{1^1}{ 1! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]]) \}$

=> $P(x_1 + x_2 \ge 2 )= 1- [[0.3678 * 0.3679] + [0.3678 * 0.3679] + [0.3678 * 0.3679] ]$

$P(x_1 + x_2 \ge 2 )= 0.5940$

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2 years ago

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Papessa [141]

Answer:

y = 14

Step-by-step explanation:

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2 years ago

Patty has just completed her second semester in college. She earned a grade of B in her 4-hour topology course, a grade of D i

umka21 [38]

Answer: 1.4

Step-by-step explanation:

To calculate the grade point average you have to sum all the points of each course multiplying the hours and then diveded by the total number of hours she did.

She earned a grade B in her 4 hour topology course, so she has 3*4 points.

In her 11 hour gouvernment course, she earned a grade D, so she has 1*11 points. In the 2 hour biology course she earned a grade D, so she has 1*2 points and in her 3 hours studio art course she had also a grade D, so she has 1*3 points

She has done 3+2+11+4 hours of subjects=20.

The total average is (3*4+1*11+1*2+1*3)/20=28/20=1.4

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3 years ago