V1=50km/h
v2=90km/h
s1=s2=6km
s=12km
The average speed over the 12 km drive:
v=s/t
The time needed to drive 12km will be:
t = t1+t2
t1=s1/v1, t2=s2/v2
t=s1/v1+s2/v2=(s1v2+s2v1)/(v1v2)
v=sv1v2/(s1v2+s2v1)=12*50*90/(6*50+6*90)=64,28 km/h
Answer:
.0888 repeating
Step-by-step explanation:
4 ÷ 5 ÷ 9 work left to right
Answer: 1/2
Step-by-step explanation: In this problem, we're tossing a coin and we want to find the probability of tossing a heads.
Now, let's find the probability of tossing a heads.
Remember that a coin has two sides which are <em>heads</em> and <em>tails</em>. When you flip a coin, each side is as likely to come up as the other. This means that the probability of flipping heads is the fraction 1/2.
Since the probability of flipping a heads is 1/2, we can also say that the probability of flipping a heads is 50%.
Therefore, the probability of flipping a heads on a fair coin is 1/2.
Answer:
Step-by-step explanation:
g(t)=t^2 - t
f(x) = (1 + x)
g(f(x)) = f(x)^2 - f(x)
g(f(x)) = (x + 1)^2 - x - 1
g(f(0)) = (0 +1)^2 - x - 1
g(f(0)) = 1 - 1 - 1 = -1
================================
f(x) = 1 + x
f(g(t)) = 1 + g(t)
f(g(t)) = 1 + t^2 - t
f(g(0)) = 1 + 0 - 0
f(g(0)) = 1
The answer I'm getting is 0.
It would be 100 since it it the closest 100
