Answer:4^\67
Step-by-step explanation:
Answer:
No
Step-by-step explanation:
Answer:
Step-by-step explanation:
The motorist drove at a distance of 90km at a constant speed for the first 40km, and then 20 km/hr faster for the rest of the journey.
The whole journey took him 1hr.
Let S denotes the average speed (in km/hr) for the first 40 km.
Hence we get the following relation,
40/S + (90 - 40)/(S + 20) = 1
or 50/(S + 20) = 1 - 40/S = (S - 40)/S
or (S + 20)(S - 40) = 50S or S^2 - 70S - 800 = 0 or (S - 80)(S + 10) = 0
or S = 80 (km/hr) [Ans]
[S cannot be negative value]
<u>Answer</u>
Center: (1,-12)
Radius: 5
<u>Work</u>
+
-2x+24y+120=0 (Subtract 120 on both sides and rearrange)
-2x+
+24y=-120 (Then divide 2 by 2 and square it. Do the same for 24.)
-2x+1+
+24y+144=-120+1+144 (You have to add the same numbers on both sides)
(Simplify)
So you would put (1,-12); r=5