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3 years ago

20 points!! help needed

Mathematics

1 answer:

dimaraw [331]3 years ago

7 0

ANSWER

1 bell shape

2 to find probability when sampling

EXPLANATION

1 In a normal distribution, the mode,mean and median are equal.

As a result, the distribution is neither skewed to the right or left.

The shape of the normal distribution looks like a bell.

That is why it is also called the bell curve.

2. The area under the normal curve is 1.

The line of symmetry of the bell shaped distribution divides it into two halves with area 0.5 each.

The normal curve is therefore used to find the probabilities of a sample distributions.

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umka2103 [35]

Answer: y=-6/5x+3

Step-by-step explanation:

To find the equation of the line that passes through the points, you want to first find the slope by using the formula $m=\frac{y_2-y_1}{x_2-x_1}$ , then solve for the y-intercept.

$m=\frac{15-(-3)}{-10-5} =\frac{18}{-15} =-\frac{6}{5}$

Now that we have the slope, we can plug in a given point and solve for the y-intercept.

15=-6/5(-10)+b [multiply]

15=12+b [subtract both sides by 12]

b=3

Now that we have the y-intercept, we know the equation is y=-6/5x+3.

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3 years ago

How do you complete this One-Step equation?<br>5 1/2 + p = 6

dalvyx [7]

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subtract 5 /12 from each side

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3 years ago

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In a fruit salad, there are 12 strawberries, 14 grapes, 6 kiwis, and 4 papayas. Find the ratio of kiwis to the total number of p

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Answer:

1:6

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2 years ago

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If a=2b^3 and b= -1/2c ^-2,express a in terms of c.

ElenaW [278]

Answer:

Part 1) $a=-\frac{1}{4c^6}$

Part 2) $a=-\frac{1}{4c^{-6}}$

Step-by-step explanation:

Part 1) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2}c^{-2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{1}{2}c^{-2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{1}{2}c^{-2})^{3}=2(-\frac{1}{2})^3(c^{-2})^{3}=2(-\frac{1}{8})(c^{-6})=-\frac{1}{4c^6}$

therefore

$a=-\frac{1}{4c^6}$

Part 2) we have

$a=2b^{3}$ ----> equation A

$b=-\frac{1}{2c^{-2}}=-\frac{c^{2}}{2}$ ----> equation B

substitute equation B in equation A

$a=2(-\frac{c^{2}}{2})^{3}$

Applying property of exponents

$(x^{m})^{n}=x^{m*n}$

$x^{-m} =\frac{1}{x^{m}}$

$a=2(-\frac{c^{2}}{2})^{3}=2(-\frac{c^{6}}{8})$

simplify

$a=-\frac{c^{6}}{4}$

therefore

$a=-\frac{1}{4c^{-6}}$

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3 years ago