Ask question

Ask question

All categories

2 years ago

5

(PLEASEHELP )Graphic artist makes covers for paperback novels, the pay is $350 per cover. If the artist draws six covers in 48 h

ours, what is their approximate hourly rate to the nearest $10?

1 answer:

djyliett [7]2 years ago

4 0

Answer:

350(6) / 48 = 43.75

Step-by-step explanation:

40$ per hour.

You might be interested in

.!.$.!.!.’!!.!!.!.!need help

artcher [175]

oml! ill try give me a min tho

7 0

2 years ago

Read 2 more answers

There was a seller of horses, who sold all his horses to three people. To the first man he sold half of all his horses and a hal

Nata [24]

Answer:

7

Step-by-step explanation:

3RD MAN: 1

2ND MAN: 2

1ST MAN: 4

3rd Man = 1/2+1/2 = 1

2nd Man = 1+1 = 2

1st Man = 2*2 = 4

7 0

2 years ago

Read 2 more answers

25 POINTS PLZ HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Andrews [41]

Answer:

87+87+81+86+89+83+89= 602. Divided by 7 because that’s how many numbers there were is 86 and that is your mean/average.

7 0

3 years ago

If anyone can help me with this geometry homework i will give you 80 dollars like fr on everything NO LINKKSS!!

Ierofanga [76]

Whats the geometry homework

3 0

2 years ago

Suppose the rate of type II diabetes in 40- to 59-year-olds is 7% among Caucasians, 10% among African-Americans, 12% among Hispa

melomori [17]

Answer:

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

Step-by-step explanation:

We have these following rates of type II diabetes:

7% among Caucasians

10% among African-Americans

12% among Hispanics

5% among Asian-Americans.

The ethnic distribution of Houston is:

30% Caucasian

25% African-American

40% Hispanic

5% Asian-American

What is the overall probability of type II diabetes among 40- to 59-year-olds in Houston?

$P = P_{1} + P_{2} + P_{3} + P_{4}$

$P_{1}$ is the probability of finding a Caucasian with type II diabetes in Houston. So it is 7% of 30%.

$P_{1} = 0.07*0.30 = 0.021$

$P_{2}$ is the probability of finding an African-American with type II diabetes in Houston. So it is 10% of 25%.

$P_{2} = 0.1*0.25 = 0.0215$

$P_{3}$ is the probability of finding a Hispanic with type II diabetes in Houston. So it is 12% of 40%.

$P_{3} = 0.12*0.40 = 0.048$

$P_{4}$ is the probability of finding an Asian-American with type II diabetes in Houston. So it is 5% of 5%.

$P_{3} = 0.05*0.05 = 0.0025$

$P = P_{1} + P_{2} + P_{3} + P_{4} = 0.021 + 0.0215 + 0.048 + 0.0025 = 0.093$

The overall probability of type II diabetes among 40- to 59-year-olds in Houston is 9.3%.

4 0

3 years ago