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Anna71 [15]
3 years ago
13

A hiker is lost in the woods. A search team has created a coordinate grid to represent the woods. Each unit on the grid is one s

quare mile. The hiker was last seen at (4, -9) and could have walked 10 miles in any direction since then. Which equation represents the area the hiker could be in?
A) (x - 4)2 + (y + 9)2 = 102
B) (x + 4)2 + (y - 9)2 = 102
C) (x + 4)2 + (y + 9)2 = 1002
D) (x - 4)2 + (y - 9)2 = 1002
Mathematics
1 answer:
prohojiy [21]3 years ago
5 0
The circle of radius r centered at (h, k) has equation
.. (x -h)^2 +(y -k)^2 = r^2

Selection A is appropriate.

_____
It would be helpful if you would use appropriate math symbols. 102 is very different from 10^2. (Copying and pasting does not work--editing is needed.)
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Work out:<br> 2/3p - 3/4 = 0.2
weqwewe [10]

Answer:

2/3p - 3/4 = 2/10

2/3p = 38/40

p = 57/40 = 1 17/40

Step-by-step explanation:

7 0
2 years ago
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Using the order of operations, what should be done first to evaluate 12 divided by (negative 6) (3) + (negative 2)? Divide 12 by
koban [17]

12 / (-6)(3) + (-2)

First divide 12 by -6

3 0
3 years ago
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A pencil cup is a cylinder made of plastic with one base missing. The cup is 5 inches tall and has a radius of 1.75 inches. Appr
wariber [46]

Answer:

74.22

Step-by-step explanation:

a pencil cup is like a cylinder

A=2πrh+2πr2=2·π·1.75·5+2·π·1.752≈74.22013

hope this helps

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3 0
3 years ago
What is the value of x?
scoray [572]

Answer:

x = 54.6 m

Step-by-step explanation:

Δ MAB and Δ MNP are similar, then corresponding sides are in proportion, that is

\frac{MA}{MN} = \frac{MB}{MP} , substitute values

\frac{80.5-35}{80.5} = \frac{x}{96.6}

\frac{45.5}{80.5} = \frac{x}{96.6} ( cross- multiply )

80.5x = 4395.3 ( divide both sides by 80.5 )

x = 54.6

8 0
3 years ago
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Please help!!!!!!!!!!
pogonyaev

Answer:

By hypotenuse - side test (HL) the two triangles are congruent.

Step-by-step explanation:

In ∆ABC and ∆DCB

i) angleABC = angleDCB.....(each 90°)

ii) BC = BC .....( common side)

iii) AC = DB.....(given)

therefore by hypo-side test ∆ABC congruent ∆DCB

5 0
3 years ago
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