Answer:
m<ZJNK=47°
Step-by-step explanation:
m<ZJNK=103°-24°-32°=47°
The given equation is: 
To find the line perpendicular to it, we interchange coefficients and switch the signs of one coefficient.
The equation to a line perpendicular to it is:
$ 2y-x=c$
where, $c$ is some constant we have determine using the condition given.
It passes through $(2,-1)$
Put the point in our equation:
$2(-1)-(2)=c$
$c=-2-2$
$c=-4$
The final equation is:
$\boxed{ 2y-x=-4}$
Basically, the equator is like the x-axis of the world and the prime meridian is like the y-axis. You locate places by distances from these lines.
The answer would be the first one or 3y2, this is because it goes into each term evenly enough to simplify it.