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Vladimir [108]
3 years ago
13

Please help ill rate brainliest!Given that line QT is a median of triangle QRS, find RS.

Mathematics
1 answer:
Agata [3.3K]3 years ago
4 0
T is the midpoint of the side RS, therefore the segments RT and TS have the same size.
Therefore: 
RT=TS
3x+3=7x-5

we have to solve this equation: 3x+3=7x-5 to find the value of "x"

3x+3=7x-5
3x-7x=-3-5
-4x=-8
x=-8/-4
x=2

We calculate the distance of RT and TS
RT=3x+3=3(2)+3=6+3=9
TS=7x-5=7(2)-5=14-5=9

We calculate the distance of RS:
RS=RT+TS=9+9=18 u

Answer: the length of RS is 18 u 
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Answer:

a) 2x^4 + 8x^3 + x^2 + 3x

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Step-by-step explanation:

Hi!

a)

The product of a sum is the sum of the products, having said this:

(2x^3 + 8x^2 + x + 3) \times x = 2x^4 + 8x^3 + x^2 + 3x

b)

We can use the result from part a and consider x = 10.

First lets take the first polynomial

2x^3 + 8x^2 + x + 3 = 2(10)^3 + 8 (10)^2+10^1+3(10)^0

Knowing that every number (excepting probably 0, which could be undefined for some or 1 for others) to the power of 0 is one:

2x^3 + 8x^2 + x + 3 = 2(1000)+ 8(100)+10+3(1) = 2813

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Now lets conisder the product of the polynomial times x and evaluate it at x=10:

(2x^3 + 8x^2 + x + 3) \times x = 2x^4 + 8x^3 + x^2 + 3x

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