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crimeas [40]
3 years ago
10

(a + b)2 for a = 2 and b = 3.

Mathematics
2 answers:
Lady_Fox [76]3 years ago
7 0

Answer:

Step-by-step explanation:

So first you would plug the values into the equation so it would be (2+3)2. The you would distribute first so multiply 2 times 2 and 3 times 2 then you would get 4+6 = 10

Dominik [7]3 years ago
5 0

Answer:

10

Step-by-step explanation:

Fill in what A and B equals

(2+3)2

solve for inside the parentheses

(5)2

then multiply

5×2=10

therefore the answer is 10

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Explain how you can rewrite the equation n+8=24 so that it involves subtraction rather than addiction
Vinil7 [7]

Answer:

n = 24 - 8.

Step-by-step explanation:

n + 8 = 24

Subtract 8 from each side:

n + 8 - 8 = 24 - 8

n = 24 - 8.

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What is the equation, in slope-intercept form, of the line that passes through (0, 3) and has a slope of −6?
crimeas [40]

Answer:

The answer is

<h2>y =  - 6x - 3</h2>

Step-by-step explanation:

To find the equation of the line given a point and slope we use the formula

<h3>y  - y_{1} = m(x - x _{1})</h3>

where

m is the slope

( x1 , y1) is the point

From the question the point is (0 , 3) and slope is - 6

Substitute the values into the above formula and solve

That's

<h3>y -  3 =  - 6(x - 0) \\ y - 3 =  - 6x</h3>

We have the final answer as

<h3>y =  - 6x - 3</h3>

Hope this helps you

8 0
3 years ago
Draw the image of ∆ABC under the dilation with scale factor 3 and center of dilation (-5, -4).
natima [27]

The image of Triangle ABC have coordinates as

A'(-2,5)

B'(-2,-1)

C'(7,-1)

Step-by-step explanation:

The figure show that Points A(-4,-1),B(-4,-3) and C(-1,-3) forms the Triangle ABC

It is asked to scaled the triangle with scale factor of 3 and centered at P(-5,-4)

For point A(-4,-1) :

Distance of A(-4,-1) from center P(-5,-4) in x-direction is 1 units and y-direction is 3 units

After scale by factor of 3,

Distance of A(-4,-1) from center P(-5,-4) is also multiply by 3

New distance in x-direction is 3 units and 9 units in y-direction from center P(-5,-4)

Therefore, New location A' is ((-5)+3,(-4)+9)=(-2,5)

For point B(-4,-3)

Distance of B(-4,-3) from center P(-5,-4) in x-direction is 1 units and y-direction is 1 units

After scale by factor of 3,

Distance of B(-4,-3) from center P(-5,-4) is also multiply by 3

New distance in x-direction is 3 units and 3 units in y-direction from center P(-5,-4)

Therefore, New location B' is ((-5)+3,(-4)+3)=(-2,-1)

For point C(-1,-3)

Distance of C(-1,-3) from center P(-5,-4) in x-direction is 4 units and y-direction is 1 units

After scale by factor of 1,

Distance of C(-1,-3) from center P(-5,-4) is also multiply by 3

New distance in x-direction is 12 units and 3 units in y-direction from center P(-5,-4)

Therefore, New location C' is ((-5)+12,(-4)+3)=(7,-1)

Therefore, The image of Triangle ABC have coordinates as

A'(-2,5)

B'(-2,-1)

C'(7,-1)

5 0
3 years ago
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