24cups is the same as

Q. Find the measure of QR

Andreas93 [3]

Answer: 22

Step-by-step explanation:

Since U is the midpoint of P and R, and S is the midpoint of P and Q, SU must be a midsegment.

By the midsegment theorem, SU is 1/2 the value of QR. Therefore QW = SU*2 = 11*2 = 22.

8 0

2 years ago

Homer is giving some cookies to each of

Stells [14]

Answer:

7 cookies

Step-by-step explanation:

We have 3 brothers

First , Second, Third

Let the total number cookies be represented by A

1 cookie = 1

Working backwards, we start from the third brother

If we work backwards

It means he gave everything away

We start from the youngest

He was given 1/2 of what was left and 1/2 a cookie

This means,

1/2 + 1/2 = 1

The second brother

He got half of what is left and 1/2 a cookies

Half of what is left from brother

= What the youngest brother got + 1/2 + 1/2 a cookie

= 1 + 1/2 + 1/2

= 1.5 + 1/2

= 2 cookies

For the first brother

He got 1/2 of the cookies + 1/2 cookie

= 1.5 × 2 + 1/2 + 1/2 cookies

= 3 1/2 + 1/2

= 4 cookies

The first brother got 4 cookies

The second brother got 2 cookies

The third broth got 1 cookies

3 0

3 years ago

A rectangular box with a volume of 272ft^3 is to be constructed with a square base and top. The cost per square foot for the bot

ASHA 777 [7]

Answer:

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

The length of one side of the base of the given box is 3 ft.

The height of the box is 30.22 ft.

Step-by-step explanation:

Given that, a rectangular box with volume of 272 cubic ft.

Assume height of the box be h and the length of one side of the square base of the box is x.

Area of the base is = $(x\times x)$

$=x^2$

The volume of the box is = area of the base × height

$=x^2h$

Therefore,

$x^2h=272$

$\Rightarrow h=\frac{272}{x^2}$

The cost per square foot for bottom is 20 cent.

The cost to construct of the bottom of the box is

=area of the bottom ×20

$=20x^2$ cents

The cost per square foot for top is 10 cent.

The cost to construct of the top of the box is

=area of the top ×10

$=10x^2$ cents

The cost per square foot for side is 1.5 cent.

The cost to construct of the sides of the box is

=area of the side ×1.5

$=4xh\times 1.5$ cents

$=6xh$ cents

Total cost = $(20x^2+10x^2+6xh)$

$=30x^2+6xh$

Let

C $=30x^2+6xh$

Putting the value of h

$C=30x^2+6x\times \frac{272}{x^2}$

$\Rightarrow C=30x^2+\frac{1632}{x}$

Differentiating with respect to x

$C'=60x-\frac{1632}{x^2}$

Again differentiating with respect to x

$C''=60+\frac{3264}{x^3}$

Now set C'=0

$60x-\frac{1632}{x^2}=0$

$\Rightarrow 60x=\frac{1632}{x^2}$

$\Rightarrow x^3=\frac{1632}{60}$

$\Rightarrow x\approx 3$

Now $C''|_{x=3}=60+\frac{3264}{3^3}>0$

Since at x=3 , C''>0. So at x=3, C has a minimum value.

The length of one side of the base of the box is 3 ft.

The height of the box is $=\frac{272}{3^2}$

=30.22 ft.

The dimensions of the box is 3 ft by 3 ft by 30.22 ft.

7 0

3 years ago

A group of fitness club members lose a combined total of 28 kg in one week there approximately 2.2 pounds and 1 kg assuming the

Akimi4 [234]

Answer:

8.8 pounds

Step-by-step explanation:

There are 7 days in a week, so the daily loss was ...

(28 kg)/(7 days) = 4 kg/day

In pounds, that is about ...

(4 kg/day)(2.2 lb/kg) = 8.8 lb/day

6 0

3 years ago

A circle with area 16pi has a sector with a central angle of 8/5pi radians. What is the area of the sector?

lianna [129]

Answer:

The area of the sector is $12.8\pi\ units^2$

Step-by-step explanation:

we know that

The area of a complete circle (16π units^2) subtends a central angle of 2π radians

so

using proportion

Find out the area of a sector , if the central angle is equal to 8π/5 radians

$\frac{16\pi}{2\pi}=\frac{x}{(8\pi/5)}\\\\x=8(8\pi/5)\\\\x= 12.8\pi\ units^2$

4 0

3 years ago

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