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luda_lava [24]
3 years ago
7

What's an equivalent ratio to 12:10 ? ( explain also too please! :D )

Mathematics
2 answers:
navik [9.2K]3 years ago
8 0
<span>12:10 equivalent ratio is 6:5

12/2 : 20/2 = 6:5
</span><span />
Nikitich [7]3 years ago
3 0
6:5 it's basically just like a fraction that you're reducing.
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The wall is 4m long and 3m board.If it has volume of 720000cm.find the height of the wall​
OLEGan [10]

Answer:

Step-by-step explanation:

l = 4m = 400 cm

w = 3m = 300 cm

Volume  = 720000 cubic cm = 720000

length * width * height = 720000

400 *  300 * height = 720000

height = 720000 / 400 * 300 = 72/12 = 6 cm

6 0
3 years ago
A store manager wants to order T-shirts with his new store logo. He's narrowed his color choices down to blue, red, white, or ye
Greeley [361]

Answer: He should order blue shirts

Step-by-step explanation:

The more votes means you should do it

38/100= .38 or 38% for blue. (HIGHEST)

25/100 = .25 or 25% for red (Third lowest)

26/100 = .26 or 26% for white. ( second highest)

11/100 = .11 or 11% for yellow (Lowest votes)

The more percentage should be the highest recoomended

Learned this today Hope this helped!

#SubToPewds

8 0
3 years ago
Read 2 more answers
One bus leaves a stop every 9minutes. A second bus leaves the stop every 15 minutes. If they both leave at 1:25 P.M., AT what ti
jasenka [17]
1:40 because 25 plus 15 equals 40 and if it went over 60 it would 2:00 so the answer is 1:40
8 0
3 years ago
What is 8 1/3x6 3/4=
BaLLatris [955]

Answer:

I think it is 56.25 not sure but try it

4 0
3 years ago
Read 2 more answers
E^(8x)+e^(-x) find the interval on which f is increasing
saveliy_v [14]
Assuming ya mean
f(x)=e^{8x}+e^{-x}
take derivitive
remember dy/dx e^x=e^x
also the chain rule

so
f'(x)=8e^{8x}+-1e^{-x}
find where it equals 0
0=8e^{8x}+-e^{-x}
e^{-x}=8e^{8x}
multiply both sides by e^x
1=8e^{9x}
divide both sides by 8
\frac{1}{8}=e^{9x}
take ln of both sides
ln(\frac{1}{8})=ln(e^{9x})
ln(\frac{1}{8})=9x
divide both sides by 9
\frac{ln(\frac{1}{8})}{9}=x

x≈-1/5
f'(-1)<0
f'(0)>0

so it is increasing from x to infinity

the interval it is increasing on is (\frac{ln(\frac{1}{8})}{9},  \infty)
6 0
3 years ago
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