1m =3.28 feet 1km= 1000m 1km=3 280 feet
120x3 280=393 600feet/h 1h=3 600sec
393 600/3 600=109.33feet/sec
Answer: i think its B not sure tho.
Step-by-step explanation:
1/3 ln(<em>x</em>) + ln(2) - ln(3) = 3
Recall that
, so
ln(<em>x</em> ¹ʹ³) + ln(2) - ln(3) = 3
Condense the left side by using sum and difference properties of logarithms:


Then
ln(2/3 <em>x</em> ¹ʹ³) = 3
Take the exponential of both sides; that is, write both sides as powers of the constant <em>e</em>. (I'm using exp(<em>x</em>) = <em>e</em> ˣ so I can write it all in one line.)
exp(ln(2/3 <em>x</em> ¹ʹ³)) = exp(3)
Now exp(ln(<em>x</em>)) = <em>x </em>for all <em>x</em>, so this simplifies to
2/3 <em>x</em> ¹ʹ³ = exp(3)
Now solve for <em>x</em>. Multiply both sides by 3/2 :
3/2 × 2/3 <em>x</em> ¹ʹ³ = 3/2 exp(3)
<em>x</em> ¹ʹ³ = 3/2 exp(3)
Raise both sides to the power of 3:
(<em>x</em> ¹ʹ³)³ = (3/2 exp(3))³
<em>x</em> = 3³/2³ exp(3×3)
<em>x</em> = 27/8 exp(9)
which is the same as
<em>x</em> = 27/8 <em>e</em> ⁹
Answer:
z^1+3z+2
Step-by-step explanation:
(z+1)(z+1)
Multiply each term in the first parenthesis by each term in the second parenthesis
Z x z+2z+z+2
Calculate the product
<u>z</u>^2 +2z+z+2
collect like terms
z^2+3z+2
2z+z
If a term doesnt have a coefficient it is considered that the coefficient is 1
2z+1z
(2+1)z
(2+1)z
3z
z^2+3z+2