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4 years ago

3x - 4y =7 solve for y

Mathematics

2 answers:

pochemuha4 years ago

5 0

Y= 3/4x - 7/4
Hope this helps

pickupchik [31]4 years ago

4 0

3x - 4y = 7...subtract 3x from both sides
-4y = -3x + 7...divide both sides by -4
y = 3/4x - 7/4 <==

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If y=-8 when x=2, find y when x=3

tatuchka [14]

I don't really know if the question is complete but...

y = x -10 can be a solution

so y would be -7 when x is 3

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3 years ago

Using the graph below, what is the value of f(6) ?

Dima020 [189]

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$f(6) = - 2$

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3 years ago

Read 2 more answers

Given the formula y = mx + b, what is the slope of a line, m, if x = 5, y = 7, and b =10?

anygoal [31]

The answer is:
C. The slope -3/5
Because -3/5 times 5 is -3 and when you combine -3 and 10 the answer is 7 and 7=7 (the y)

3 0

3 years ago

What is the slope of the line?<br> 3x-4y=7

Vinvika [58]

Answer:

3/4

Step-by-step explanation:

3x - 4y = 7.....subtract 3x from both sides

-4y = -3x + 7 ...now we divide both sides by -4

(-4/-4)y = (-3/-4)x + (-7/4)...simplify

y = 3/4x - 7/4

y = mx + b

y = 3/4x - 7/4.....so the number in the m position is 3/4 <== ur slope

5 0

3 years ago

Read 2 more answers

If <img src="https://tex.z-dn.net/?f=%20300cm%5E%7B2%7D%20" id="TexFormula1" title=" 300cm^{2} " alt=" 300cm^{2} " align="absmid

Artist 52 [7]

Check the picture below. Recall, is an open-top box, so, the top is not part of the surface area, of the 300 cm². Also, recall, the base is a square, thus, length = width = x.

$\bf \textit{volume of a rectangular prism}\\\\
V=lwh\quad 
\begin{cases}
l = length\\
w=width\\
h=height\\
-----\\
w=l=x
\end{cases}\implies V=xxh\implies \boxed{V=x^2h}\\\\
-------------------------------\\\\
\textit{surface area}\\\\
S=4xh+x^2\implies 300=4xh+x^2\implies \cfrac{300-x^2}{4x}=h
\\\\\\
\boxed{\cfrac{75}{x}-\cfrac{x}{4}=h}\\\\
-------------------------------\\\\
V=x^2\left( \cfrac{75}{x}-\cfrac{x}{4} \right)\implies V(x)=75x-\cfrac{1}{4}x^3$

so.. that'd be the V(x) for such box, now, where is the maximum point at?

$\bf V(x)=75x-\cfrac{1}{4}x^3\implies \cfrac{dV}{dx}=75-\cfrac{3}{4}x^2\implies 0=75-\cfrac{3}{4}x^2
\\\\\\
\cfrac{3}{4}x^2=75\implies 3x^2=300\implies x^2=\cfrac{300}{3}\implies x^2=100
\\\\\\
x=\pm10\impliedby \textit{is a length unit, so we can dismiss -10}\qquad \boxed{x=10}$

now, let's check if it's a maximum point at 10, by doing a first-derivative test on it. Check the second picture below.

so, the volume will then be at $\bf V(10)=75(10)-\cfrac{1}{4}(10)^3\implies V(10)=500 \ cm^3$

6 0

3 years ago