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borishaifa [10]
3 years ago
15

there was a red brick and pink bricks and green bricks and a yellow square . what is the odd one in world form

Mathematics
1 answer:
Anna [14]3 years ago
3 0

yellow square even though im pretty sure it doesn't matter now

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The answers are A, B, D, and F

Step-by-step explanation:

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PLEASE HELP A student at a university makes money by buying and selling used cars. Charles bought a used car and later sold it f
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Answer: Charles bought a used car and later sold it for a 20% profit. If he sold it for $4680, how much did Charles pay for the car?

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Let the price he paid equal "x".

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Guys please help me match these<br><br> Brainliest will go to the right answer
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Step-by-step explanation:

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2 years ago
An elevator descends into a mine shaft at the rate of 6 m/min. If the descend starts from 20 meter above the ground level, how l
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Please Help. I really don’t get this concept, if you could explain it in detail it would be very appreciated
Dafna11 [192]
<h3>Answer: 24/25</h3>

=================================================

Explanation:

Sine is given to be negative, and so is tangent. This only happens in quadrant Q4

Recall that y = sin(theta), so if sin(theta) < 0, then we're below the x axis.

If tan(theta) < 0, then this means cos(theta) > 0

So we have y < 0 and x > 0 which places the angle somewhere in Q4.

--------------------------

Draw a right triangle as shown below in the attached image. We have AC = 25 and BC = 7. Use the pythagorean theorem to find that AB = 24

So this is what your steps may look like

a^2+b^2 = c^2

7^2+b^2 = 25^2

b^2+49 = 625

b^2 = 625-49

b^2 = 576

b = sqrt(576)

b = 24

So because AB = 24, we know that the cosine of the angle is adjacent/hypotenuse = 24/25

---------------------------

As an alternative, you could use the trig identity

sin^2(x) + cos^2(x) = 1

and plug in the given value of sine to solve for cosine. The cosine value result will be positive since we're in Q4.

So,

sin^2(x) + cos^2(x) = 1

(-7/25)^2 + cos^2(x) = 1

(49/625) + cos^2(x) = 1

cos^2(x) = 1 - (49/625)

cos^2(x) = (625/625) - (49/625)

cos^2(x) = (625-49)/625

cos^2(x) = 576/625

cos(x) = sqrt(576/625)

cos(x) = sqrt(576)/sqrt(625)

cos(x) = 24/25

This is effectively a rephrasing of the previous section since the pythagorean trig identity is more or less the pythagorean theorem (just in a trig form)

6 0
3 years ago
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