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Irina18 [472]
3 years ago
14

Sara bought a used car for $10,000. She learned from online that the value of a car depreciated 15% per year. What is the formul

a for the value of Sam's car after t years? Also, what would be the value of Sam's car in 5 years?
Mathematics
1 answer:
Fudgin [204]3 years ago
4 0

Answer:

Step-by-step explanation:

Value of Sam's car after t years =

==10000*(1-\frac{15}{100})^{t}\\\\=10000*(\frac{85}{100})^{t}\\\\=10000*(0.85)^{t}

Value of Sam's car in 5 years=

=10000*(0.85)^{5}\\\\=10000*0.4437\\\\

= $ 4437

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Write an equation in general form for the line passing through (-12,-1) and perpendicular to the line whose equation is 6x-y-4=0
Rus_ich [418]

The Solution:

Given the equation of a line:

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We are required to find the equation of a line that is perpendicular to the given line and passes through the point (-12,-1).

Step 1:

Determine the slope of 6x-y-4=0.

\begin{gathered} \text{  Express y in terms of x.} \\ 6x-4=y \\ y=6x-4 \end{gathered}

The coefficient x, after making y the subject of the formula, is the slope of the given line. That is:

\begin{gathered} \text{ The slope of }6x-y-4=0\text{ is 6} \\  \\ Slope=m_1=6 \end{gathered}

Step 2:

Find the slope of the required line:

Since the two lines are perpendicular, the slope is:

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Step 3:

Find the equation of the line that passes through point (-12,-1)

By formula,

y-y_1=m_2(x-x_1)

In this case,

\begin{gathered} x_1=-12 \\ y_1=-1 \end{gathered}

Substituting these values in the formula, we get the required equation is:

\begin{gathered} y--1=\frac{-1}{6}(x--12) \\  \\ y+1=-\frac{1}{6}(x+12) \end{gathered}

Cross multiplying, we get

\begin{gathered} 6y+6=-x-12 \\  \\ 6y+x+6+12=0 \\  \\ 6y+x+18=0 \end{gathered}

Therefore, the correct answer is:

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1 year ago
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Answer:

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