The number of kilometres travelled by the satellite in discuss in which case, the satellite makes 8 revolutions around the earth is; C = 177,271.8 km.
<h3>What is the distance in kilometres covered by the satellite after 8 revolutions?</h3>
Given from the task content, the earth's diameter is; 6371 km and since, the height at which the satellite orbits the earth is; 343km, it follows that the diameter of orbit if the satellite in discuss is;
D = 6371 + (343)×2
Hence, we have; diameter, D = 7057 km.
Hence, the distance travelled after 8 revolutions is;
C = 8 × πd
C = 8 × 3.14 × 7057
C = 177,271.8 km.
Read more on circumference of a circle;
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The value of x is the number inside the parenthesis, so h(-4) gives x a value of -4.
The equation says when X is ≤ -4 use the first equation
So h(-4) = -1/2(x) -15
= -1/2(-4) -15
= 2 -15
= -13
When x = -2 (h(-2) ) use the 2nd equation:
h(-2) = 20-3x^2
=20-3(-2)^2
= 20-3(4)
=20-12
=8
Now you have -13 + 3(8)
= -13 + 24
=11
The answer should be 11
It is not linear. Check to see if the points fit in any of the equations. Use 3 for x and 1 for y. None of them work. You get false statements like 3=1.
