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hjlf
4 years ago
7

During the spring concert there will be 12 choral pieces,4 solo performances, and 3 dance routines. Show all thre forms of the r

atio
Mathematics
1 answer:
zaharov [31]4 years ago
7 0
The ratio of all three forms are 12:4:3
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What is the value of 3 in 23
GuDViN [60]
3 is in the ones place.  It's value is 3 ones or 3.

2 is in the tens place, so it's value is 2 tens or 20.
6 0
4 years ago
Read 2 more answers
Sarah is making strings of beads in the first string she uses 3 beads and she triples the number of beads in each of the next st
xenn [34]

Answer:

She uses 243 beads for the 5th string.

Step-by-step explanation:

In this problem, we can see a pattern. If she triples the number of beads in each of the next strings, that means that we just take the last number and multiply by 3. If the first string uses 3, then:

The second uses 9, 3 * 3 = 9

The third uses 27, 9 * 3 = 27

The fourth uses 81, 27 * 3 = 81

And the 5th uses 243, 81 * 3 = 243.

6 0
4 years ago
In ΔUVW, \overline{UW}
kozerog [31]
Answer: is extended through point W to point X angle


Explanation
8 0
3 years ago
The equation of line L is 3x − 4y = 24. The line intersects the X − axis at A and the
zhenek [66]

Answer:

Gradient=¾

Step-by-step explanation:

Write the equation in slope-intercept form y=mx+c

3x-4y=24

-4y=24-3x

y=24/-4-3x/-4

y=-6+¾x

y=¾x-6

The gradient is therefore ¾

The y-intercept of the line occurs at(0,-6)

The x-intercept of the line occurs at(8,0)

Finding the midpoint of the two intercepts

{(x1+x2)/2,(y1+y2)/2}

M={0+8/2,(-6+0/2)}

M={8/2,-6/2}

M=(4,-3)

As you can see, the other information was not required to solve it

8 0
3 years ago
Meg rowed her boat upstream a distance of 45 mi and then rowed back to the starting point. The total time of the trip was 14 hou
Montano1993 [528]
Recall your d = rt.

so hmm is about the same as the other one... so say the boat has a speed rate of "b", well, going downstream the boat goes say " b + 2 ", because the current is adding to it, and going upstream is " b - 2 " because the current is eroding from it.

So if the whole trip took 14 hours, say it took "t" hours going upstream, then going downstream it took the slack or " 14 - t ".

Also notice, the trip forth and back is the same 45 miles.

\bf \begin{array}{lccclll}
&\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\
&------&------&------\\
Upstream&45&b-2&t\\
Downstream&45&b+2&14-t
\end{array}
\\\\\\
\begin{cases}
45=t(b-2)\implies \frac{45}{b-2}=\boxed{t}\\\\
45=(b+2)(14-t)\\
----------\\
45=(b+2)\left( 14- \boxed{\frac{45}{b-2}}\right)
\end{cases}
\\\\\\
\cfrac{45}{b+2}=14- {\cfrac{45}{b-2}}\implies \cfrac{45}{b+2}=\cfrac{14(b-2)~-~45}{b-2}

\bf \cfrac{45}{b+2}=\cfrac{14b-28-45}{b-2}\implies \cfrac{45}{b+2}=\cfrac{14b-73}{b-2}
\\\\\\
45(b-2)=(b+2)(14b-73)\implies 45b-90=14b^2-45b-146
\\\\\\
0=14b^2-90b-56\implies 0=7b^2-45b-28
\\\\\\
0=(7b+4)(b-7)\implies b=
\begin{cases}
-\frac{4}{7}\\\\
\boxed{7}
\end{cases}
6 0
3 years ago
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