Leroi’s account

$100
After first deposit = $100+$10=$110
After second deposit= $110 + $10 = $120

Sylvia’s account

$100
10% of $100 is $10
After first deposit = $100+ $10 = $110
10% of $110 = $11
After second deposit = $110 + $11 = $121

Therefore after their first deposit, both will have the same value in their accounts.
But after the second deposit, Sylvia will have 1$ more in her account than Leroi.

7 0

3 years ago

Read 2 more answers

A- 13<br> B- 26 <br> C- 52<br> D- there is not enough information

KengaRu [80]

Well...

DB is a median... It means DB divides AC in 2 equal parts. AC = 26. AB = 26 ÷ 2 = 13.

I hope I helped you.

3 0

3 years ago

Sin F = bc a/b c/a a/c

Gekata [30.6K]

$\\ \rm\Rrightarrow sin\Theta=\dfrac{Perpendicular}{Hypotenuse}$

$\\ \rm\Rrightarrow sinF=\dfrac{GE}{FG}$

$\\ \rm\Rrightarrow sinF=\dfrac{a}{c}$

3 0

3 years ago

Read 2 more answers

Arrange these functions from the greatest to the least value based on the average rate of change in the specified interval.

Romashka [77]

By definition, the average change of rate is given by:
$AVR = \frac{f(x2)-f(x1)}{x2-x1}$
We will calculate AVR for each of the functions.
We have then:

f(x) = x^2 + 3x interval: [-2, 3]:
$f(-2) = x^2 + 3x = (-2)^2 + 3(-2) = 4 - 6 = -2

f(3) = x^2 + 3x = (3)^2 + 3(3) = 9 + 9 = 18$
$AVR = \frac{-2-18}{-2-3}$
$AVR = \frac{-20}{-5}$
$AVR = 4$

f(x) = 3x - 8 interval: [4, 5]:
$f(4) = 3(4) - 8 = 12 - 8 = 4 f(5) = 3(5) - 8 = 15 - 8 = 7$
$AVR = \frac{7-4}{5-4}$
$AVR = \frac{3}{1}$
$AVR = 3$

f(x) = x^2 - 2x interval: [-3, 4]
$f(-3) = (-3)^2 - 2(-3) = 9 + 6 = 15

f(4) = (4)^2 - 2(4) = 16 - 8 = 8$
$AVR = \frac{8-15}{4+3}$
$AVR = \frac{-7}{7}$
$AVR = -1$

f(x) = x^2 - 5 interval: [-1, 1]
$f(-1) = (-1)^2 - 5 = 1 - 5 = -4

f(1) = (1)^2 - 5 = 1 - 5 = -4$
$AVR = \frac{-4+4}{1+1}$
$AVR = \frac{0}{2}$
$AVR = 0$

Answer:
these functions from the greatest to the least value based on the average rate of change are:
f(x) = x^2 + 3x
f(x) = 3x - 8
f(x) = x^2 - 5
f(x) = x^2 - 2x

5 0

4 years ago