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4 years ago

Which coefficient is needed in front of NaNO3 to balance the equation Na2S + Zn(NO3)2 → ZnS + _NaNO3? 1 2 5 7

Chemistry

2 answers:

statuscvo [17]4 years ago

7 0

The coefficient that is needed in front of NaNO3 to balance the equation is 2

Explanation

Coefficient is the number in front of a formula in a balanced chemical equation.

For equation to balance the number of atoms in product side must be equal to number of atoms in reactant side.

Putting coefficient 2 in front of NaNO3 balance the equation therefore the balanced equation is as below.

Na₂S + Zn(NO₃)2 → ZnS + 2 NaNo₃.

barxatty [35]4 years ago

3 0

There are 2 Na and 2 NO3 on the left side so there must be 2 NaNO3 on the right side. !st Law of thermodynamics: Mass cannot be created nor destroyed .

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Eva8 [605]

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3 years ago

A solid powder is known to be a mixture of NaCl and Na2CO3, but the relative amounts of each compound in the sample are unknown.

AveGali [126]

Answer:

Concentration of sodium carbonate in the solution before the addition of HCl is 0.004881 mol/L.

Explanation:

$Na_2CO_3(aq) +2 HCl(aq)\rightarrow 2NaCl(aq) + H_2O(l)+CO_2(g)$

Molarity of HCl solution = 0.1174 M

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Moles of HCl = n

$molarity=\frac{moles}{Volume (L)}$

$0.1174 M=\frac{n}{0.08315 L}$

$n=0.1174 M\times 0.08315 L=0.009762 mol$

According to reaction , 2 moles of HCl reacts with 1 mole of sodium carbonate.

Then 0.009762 mol of HCl will recat with:

$\frac{1}{2}\times 0.009762 mol=0.004881 mol$

Moles of Sodium carbonate = 0.004881 mol

Volume of the sodium carbonate containing solution taken = 1L

Concentration of sodium carbonate in the solution before the addition of HCl:

$[Na_2CO_3]=\frac{0.004881 mol}{1 L}=0.004881 mol/L$

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3 years ago

Help me pretty please

almond37 [142]

Answer:

I think it is D

Explanation:

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3 years ago

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