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jonny [76]
3 years ago
12

What can you tell by tracking oxidation numbers?

Chemistry
1 answer:
Alla [95]3 years ago
7 0

<u>Answer</u>:

By tracking oxidation numbers we can identify the number electron in the atom

<u>Explanation</u>:

Tracking of electrons helps us to know when and how many electrons get transferred from one atom to other atom . Oxidation  referred as the “loss of one or more electrons” by an atom. When the oxidation number of an element increases, there is a loss of electrons and that element is being oxidized. Oxidation numbers are usually written with the sign (+plus or −minus) followed by the magnitude, which is the opposite of charges on ions. In their elemental stage oxidation number of an atom is zero.  

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Answer:

c ammonium hydroxide nh4oh has higher ph value and its a base

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2 years ago
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What is the hybridization of the carbon atoms in 1,3-butadiene, h2c=ch-ch=ch2?
Natalija [7]
The main formula is as follow  is explained in the attached file  (please look at the examples)

the 1,3- butadiene is h2c=ch-ch=ch2, so we have 

sp²             sp²     sp²               sp²
h2c    =     ch   -     ch         =      ch2

<span>the hybridization of the carbon atoms  is </span>sp²  : trigonal planar

4 0
3 years ago
Find the volume of hydrogen gas formed when 1.5g of aluminum reacts with aq NaOH at 27 degrees Celcius.
Rudiy27

Answer:

how can I solve this ?4Al+3O2 produce 2Al2O3 find a) oxygen atoms needed to react with 5.4 g of aluminium b) grams of oxygen needed to react with 0.6 mol of aluminium?

(A) n=m/M,

n(Al)=5.4/27=0.2 moles

n(O2)=n(Al)*3/4=0.2*3/4=0.15 moles

Number of oxygen atoms= n(O2)*Avogadro's number

=0.15*6.02*10^23=9.03*10^22 oxgyen atoms

(B)

n=m/M

n(Al)=0.6/27=0.02222 moles

n(O2)=n(Al)*3/4=0.016666 moles

m=n*M

m(O2)=0.0166666*32=0.53333 grams

8 0
2 years ago
"M" represents a metallic element, the oxide of which has the formula M2O. The formula of the chloride of M is..................
Rus_ich [418]
The formula of the chloride of M will be MCI2.
8 0
3 years ago
Acetylene gas is often used in welding torches because of the very high heat produced when it reacts with oxygen gas, producing
rodikova [14]

Answer:

0.225 mol = 0.23 mol to 2 significant figures

Explanation:

Calculate the moles of oxygen needed to produce 0.090 mol of water

The equation of the reaction is given as;

2 C2H2 + 5 O2 --> 4 CO2 + 2 H2O

From the equation of the reaction;

5 mol of O2 produces 2 mol of H2O

x mol of O2 produces 0.090 mol of H2O

5 = 2

x = 0.090

x = 0.090 * 5 / 2

x = 0.225 mol

8 0
3 years ago
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