Answer:12= 24/2
Step-by-step explanation:
I'll pick B Hope this helps
Answer:
The car is actually moving at a speed more than 80 miles per hour
Step-by-step explanation:
Theoretically, since the speedometer of the car is at 80, it means the car is having a speed of 80 miles / hr. The car should move by a distance of 80 miles in an hour.
But, practically changing the tire size can affect the speedometer accuracy because larger tire covers more ground in each complete revolution. So, the actual speed is higher than the speedometer reads.
<u>Example</u>
Suppose a car comes with factory-installed tires which are 21.8 inches in diameter. It means that the circumference of each tire is 68.5 inches. Now if we replace the old tires with new tires having 24.6 inches as diameter then each new tire has a circumference of 77.3 inches. This means the car travels almost 10 inches more with each complete revolution. This can tremendously affect the reading on the speedometer. The speedometer will now indicate a speed which is too slow by almost 13%. When the speedometer reads 60 miles/hour, the car will actually be traveling at a speed of 67.7 miles/hour.
This question is incomplete, the complete question is;
Determine if the described set is a subspace. Assume a, b, and c are real numbers.
The subset of R³ consisting of vectors of the form ![\left[\begin{array}{ccc}a\\b\\c\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Da%5C%5Cb%5C%5Cc%5Cend%7Barray%7D%5Cright%5D)
, where abc = 0
- The set is a subspace
- The set is not a subspace
Answer:
Therefore; The set is not a subspace
Step-by-step explanation:
Given the data the question;
the subset R³;
S = { , where abc = 0 }
we know that a subset of R³ is a subspace if it stratifies the following properties;
- it contains additive identity
- it is closed under addition
- it is closed under scales multiplication
Looking at the properties, we can say that it is not a subspace
As;
u = ![\left[\begin{array}{ccc}1\\1\\0\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C1%5C%5C0%5Cend%7Barray%7D%5Cright%5D)
∈ S and v = ![\left[\begin{array}{ccc}0\\1\\1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D0%5C%5C1%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
∈ S
As 1×1×0=0 0×1×1=0
But u+v = ![\left[\begin{array}{ccc}1+0\\1+1\\0+1\end{array}\right] =](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%2B0%5C%5C1%2B1%5C%5C0%2B1%5Cend%7Barray%7D%5Cright%5D%20%3D)
![\left[\begin{array}{ccc}1\\2\\1\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%5C%5C2%5C%5C1%5Cend%7Barray%7D%5Cright%5D)
∉ S as 1×2×1 ≠ 0
Hence, it is not closed under addition.
Therefore; The set is not a subspace
Hello there!
-3| 2x + 6| = -12
2x + 6 = -12/-3
2x + 6 = 4
Solve absolute value
We know that 2x + 6 = 4 or 2x + 6 = -4
We have two possibilities to solve this.
1)
2x + 6 = 4
2x = 4 - 6
2x = -2
Divide both sides by -2
2x/-2 = -2/-2
x = 1
2) 2x + 6 = -4
2x = -4 - 6
2x = -10
Divide both sides by 2
2x/2 = -10/2
x = -5
Answer : X = -1 or X = -5
A+ Guaranteed!
