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Degger [83]
3 years ago
8

There are 17 portable mini suites (a.k.a. cages) in a row at the paws and claws holiday pet resort. they are neatly labeled with

their guests' names. there are 8 poodles and 9 tabbies. how many ways can the "suites" be arranged if:
Mathematics
1 answer:
DiKsa [7]3 years ago
4 0
Given that there are 17 portable mini suites (a.k.a. cages) in a row at the Paws and Claws Holiday Pet Resort. They are neatly labeled with their guests' names. There are 8 poodles and 9 tabbies. How many ways can the "suites" be arranged if: a) there are no restrictions.

b) cats and dogs must alternate.

c) dogs must be next to each other.

d) dogs must be next to each other and cats must be next to each other.


Part A:

If there are no restrictions, then the number of ways the "suites" can be arranged is given by:

17!=17\times16\times15\times14\times13\times12\times11\times10\times9\times8\times7\times6\times5\times4\times3\times2\times1=355,687,428,096,000 \ ways



Part B:

If cats and dogs must alternate, then the number of ways the "suites" can be arranged is given by:

9!\times8!=9\times8\times7\times6\times5\times4\times3\times2\times1\times8\times7\times6\times5\times4\times3\times2\times1=14,631,321,600 \ ways



Part C:

If dogs must be next to each other, then the group of dogs are taken as 1 object and there are now 10 objects to arrange. The number of ways to arrange 10 objects is given by:

10!=10\times9\times8\times7\times6\times5\times4\times3\times2\times1=3,628,800
 \ ways

Also, the group of dogs can be arranged in:

8!=8\times7\times6\times5\times4\times3\times2\times1=40,320
 \ ways

Therefore, the total number of ways the "suites" can be arranged is given by:

10!\times8!=3,628,800\times40,320=146,313,216,000 \ ways



Part D:

If dogs must be next to each other and cats must be next to each other, then the group of dogs are taken as 1 object and the group of cats are taken as 1 object, then there are now 2 objects to arrange.

The number of ways to arrange two objects is given by:

2!=2\times1=2

The number of ways the 9 dogs are to be arranged is given by:

9!=9\times8\times7\times6\times5\times4\times3\times2\times1=362,880

The number of ways the 8 cats are to be arranged is given by:
8!=8\times7\times6\times5\times4\times3\times2\times1=40,320

Therefore, the total number of ways the "suites" can be arranged is given by:

2!\times9!\times8!=2\times362,880\times40,320=29,262,643,200 \ ways
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Answer:

Solution :-

To find the least number which when divided by 6, 15 and 18 leaves a remainder 5 in each case, we have to find the L.C.M. of 6, 15 and 18 and then add 5 in that number.

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