Using the confidence interval, the margin of error is 0.02.
In the given equation we have to find the margin of error.
The resulting confidence interval for the proportion of students applying for college is (0.65,0.69).
Let p = population proportion of students applying for college
P = Sample proportion of students applying for college
ME = margin of error
So the confidence interval
CI = (P-ME, P+ME)
From the given question;
(P-ME, P+ME) = (0.65,0.69)
So lower bound= P-ME = 0.65............................(1)
Upper Bound = P+ME = 0.69............................(2)
Simplifying the Equation 1 and 2
Add equation 1 and 2 we get
2P = 1.34
Divide by 2 on both side we get
P = 0.67
Putting the value of P in the equation 2
P+ME = 0.69
0.67+ME=0.69
Subtract 0.67 on both side we get
ME = 0.02
Hence, the margin of error is 0.02.
To learn more about margin of error link is here
brainly.com/question/10501147
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