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Daniel [21]
3 years ago
9

Question in picture. Please Help! Thanks

Mathematics
1 answer:
laila [671]3 years ago
7 0

Answer:

b

Step-by-step explanation:

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What are the zeros of the function g(x) = (x + 6) (x – 4)(x + 2) ?
vitfil [10]

9514 1404 393

Answer:

  x in {-6, -2, 4}

Step-by-step explanation:

The zero product rule tells you that a product will be zero if and only if one of the factors is zero. These binomial factors are zero when x has a value that is opposite the constant of the binomial.

  x +6 = 0   ⇒   x = -6

  x -4 = 0   ⇒   x = 4

  x +2 = 0   ⇒   x = -2

The zeros of the function are the x-values -6, -2, and 4.

5 0
3 years ago
Which expression calculates the speed in meters per second of an object that travels a distance of 40 m every 10 s?
Mumz [18]

Answer:

A

Step-by-step explanation:

40/10 will give you your answer

40/10=4m/s

3 0
2 years ago
Read 2 more answers
The position vector for a particle moving on a helix is
topjm [15]

Answer:

a) 25.15

b)

   x = 1

   y = t

   z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c) (x,y) = (1, -2pi)

Step-by-step explanation:

a)

First lets calculate the velocity, that is, the derivative of c(t) with respect to t:

v(t) = (-sin(t), cos(t), 2t)

The velocity at t0=4pi is:

v(4pi) = (0, 1, 8pi)

And the speed will be:

s(4pi) = √(0^2+1^2+ (8pi)^2) = 25.15

b)

The tangent line to c(t) at t0 = 4pi has the parametric form:

(x,y,z) = c(4pi) + t*v(4pi)

Since

 c(4pi) = (1, 0, (4pi)^2)

The tangent curve has the following components:

x = 1

y = t

z = (4pi)^2 + t *(8pi) = 4pi(4pi + 2t)

c)

The intersection with the xy plane will occurr when z = 0

This happens at:

  t1 = -2pi

Therefore, the intersection will occur at:

(x,y) = (1, -2pi)

6 0
3 years ago
Two airplanes leave the airport. Plane A departs at a 44° angle from the runway, and plane B departs at a 40° angle from the run
lawyer [7]

Answer: Answer:

Plane B was farthest away from the airport

Step-by-step explanation:

"This question requires you to visualize the run way as the horizontal distance to be covered, the height from the ground as the height gained by the plane after take of and the distance from the airport as the displacement due to the angle of take off.

In plane A

The take-off angle is 44° and the height gained is 22 ft.

Apply the relationship for sine of an angle;

Sine Ф°= opposite side length÷hypotenuse side length

The opposite side length is the height gained by plane which is 22 ft

The angle is 44° and the distance the plane will be away from the airport after take-off will be represented by the value of hypotenuse

Applying the formula

sin Ф=O/H where O=length of the side opposite to angle 44° and H is the hypotenuse

In plane B

Angle of take-off =40°, height of plane=22miles finding the hypotenuse

Solution

After take-off and reaching a height of 22 ft from the ground, plane A will be 31.67 miles from the airport

After take-off and reaching a height of 22 ft from the ground, plane B will be 34.23 miles away from the airport."

Excerpt from Brainly

3 0
2 years ago
Read 2 more answers
Find the product -3,-4.-2.5
Assoli18 [71]

Answer:

-30

Step-by-step explanation:

-3(-4)(-2.5)

Apply rule -(-a) = a

=-3*4*2.5

Multiply the numbers: 3*4*2.5=30

=-30

6 0
3 years ago
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