Question

Solve the system of linear equations using any method 6x+6y=-6, 5x+y=-13

Answer 1

Answer:

x=-3

y=2

Step-by-step explanation:

To solve this problem you can use the elimination method:

- Multiply the second equation by -6:

$(-6)5x+y=-13\\-30x-6y=78$

- Add both equations:

$6x+6y=-6\\-30x-6y=78\\-------\\-24x=72\\x=-3$

- Substitute the value of x into one of the original equations and solve for y:

$6(-3)+6y=-6\\-18+6y=-6\\6y=12\\y=2$

Answer 2

Answer:

x = -3 and y = 2 is the solution.

Step-by-step explanation:

we have given system of equations:

6x+6y=-6           equation I

5x+y = - 13          equation II

we solve this system of equation  by using elimination method.

multiplying the equation II by - 6.

(-6)5x + ( -6 )y = ( - 6 ) (- 13 )

-30 x - 6 y = 78      equation  III

adding equation   I and III we have

6x + 6y = - 6

-30x -6y =78

_____________

- 24 x = 72

x =  - 3

substituting value of x in any of original equations and solve it for y.

we are putting the value of x in equation I and solve it for y

6( -3 )+ 6y = -6

-18 + 6y = -6

6y = 12

y = 2

so, x = -3 and y = 2 is the solution of given system of equations.