<u>Q</u><u>uest</u><u>ion</u><u>:</u>
To Simplify:
118 {121÷(11×11)-(-4)-(3-7)}
<u>Solu</u><u>tion</u>:
↠118 {121÷121+4-(-4)}
↠118 {1+4+4}
↠118 {5+4}
↠118{9}
↠118×9
↠1062
▬▬▬▬▬▬▬▬▬▬▬▬
The upper Solution is done by applying BODMAS
<u>Abou</u><u>t</u><u> </u><u>BODMAS</u><u>:</u>
B→ Bracket
O→ Of
D→ Division
M→ Multiplication
A→ Addition
S→ Subtraction
Answer:
1, 3, 7, 21
Step-by-step explanation:
1, 3, 7, 21
(The bolded is one factor and the other that is not bolded is another factor)
1 times 21 is 21
3 times 7 is 21
Answer:
Step-by-step explanation:
Answer:
m∠M = 79°
m∠N = 66°
Step-by-step explanation:
∠MPN is supplementary to ∠MPQ, so m∠MPN = 35
The sum of the measures of a triangle is 180.
So, m∠M + m∠N + m∠MPN = 180
5y + 4 + 4y + 6 + 35 = 180
9y + 45 = 180
9y = 135
y = 15
m∠M = 5y + 4 = 5(15) + 4 = 75 + 4 = 79
m∠N = 4y + 6 = 4(15) + 6 = 66
Another way to do this problem, which is easier, is to know that an exterior angle of a triangle is equal to the sum of the two remote interior angles.
That means 5y + 4 + 4y + 6 = 145
9y + 10 = 145
9y = 135
y = 15
From knowing the value of y you can now find the measures of angles M and N
