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Lilit [14]
3 years ago
9

A truck with a heavy load drove from Boston to New York at 45 mph. After unloading, it returned from New York to Boston at a spe

ed of 65 mph. What was its average speed for the whole trip?
Mathematics
1 answer:
V125BC [204]3 years ago
6 0
The distances from Boston to New York and New York to Boston stayed the same.  Going was 45mph and returning was 65mph.  The average would just be the sum of the two, divided by 2

(45+65)/2 = 55mph average
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the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard dev
Naya [18.7K]

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a) 2.84% probability that he is late for his first lecture.

b) 5.112 days

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When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

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\mu = 16, \sigma = 2.1

a. Find the probability that he is late for his first lecture.

This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{20 - 16}{2.1}

Z = 1.905

Z = 1.905 has a pvalue of 0.9716

1 - 0.9716 = 0.0284

2.84% probability that he is late for his first lecture.

b. Find the number of days per year he is likely to be late for his first lecture.

Each day, 2.84% probability that he is late for his first lecture.

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0.0284*180 = 5.112 days

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