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Ivan
4 years ago
6

At work one day , Ricardo had to go down 3 floor to go to meetings. Then he had to go up 7 floors for another meeting.What will

Ricardo need to go to get back to the floor were he started

Mathematics
1 answer:
mestny [16]4 years ago
4 0
Ricardo would have to go 4 floors down to reach the floor he started in cause 
7-3=4 floors
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How many soultions does 5(x-3)+6=5x-9
olya-2409 [2.1K]

5(x - 3) + 6 = 5x - 9 has no solution

<em><u>Solution:</u></em>

We have to find the number of solutions for the given equation

Given equation is:

5(x - 3) + 6 = 5x - 9

Multiply the terms inside with bracket with constant outside the bracket

5x - 15 + 6 = 5x - 9

Add the constants in left hand side of equation

5x - 9 = 5x - 9

If the coefficients are the same on both sides, then the sides will not equal, therefore no solutions will occur.

Here, 5x - 9 = 5x - 9

The coefficients are same in both sides of equation

Therefore, the equation has no solution

5 0
3 years ago
Rep viuen
Keith_Richards [23]

Answer:

8 and -4

Step-by-step explanation:

8*-4=-32

8+(-4)=4

7 0
3 years ago
Michael can buy 4 sandwiches and 3 cups of coffee for $23.75. Amy can buy 2 sandwhiches and 5 cups of coffee for $19.75 how much
Kobotan [32]

Answer: The cost of one sandwich is $4.25 and the cost of one cup of coffee is $2.25.

Step-by-step explanation:

Let x be the cost of one sandwich and y be the cost of one cup of coffee.

By considering the given situation, we have the following equations :-

4x+3y=23.75.................(1)\\\\2x+5y=19.75................(2)

Multiply 2 on both sides of equation (2) , we get

4x+10y=39.5................(3)

Subtract equation (1) from equation (3), we get

7y=15.75\\\\\Rightarrow\ y=\dfrac{15.75}{7}=2.25

Put value of y in (1), we get

4x+3(2.25)=23.75\\\\\Rightarrow\ 4x+6.75=23.75\\\\\Rightarrow\ 4x =17\\\\\Rightarrow\ x=4.25

Hence, the cost of one sandwich is $4.25 and the cost of one cup of coffee is $2.25.

8 0
3 years ago
(a) A lamp has two bulbs, each of a type with average lifetime 1400 hours. Assuming that we can model the probability of failure
Temka [501]

Answer:

For first lamp ; The resultant probability is 0.703

For both lamps; The resultant probability is 0.3614

Step-by-step explanation:

Let X be the lifetime hours of two bulbs

X∼exp(1/1400)

f(x)=1/1400e−1/1400x

P(X<x)=1−e−1/1400x

X∼exp⁡(1/1400)

f(x)=1/1400 e−1/1400x

P(X<x)=1−e−1/1400x

The probability that both of the lamp bulbs fail within 1700 hours is calculated below,

P(X≤1700)=1−e−1/1400×1700

=1−e−1.21=0.703

The resultant probability is 0.703

Let Y be a lifetime of another lamp two bulbs

Then the Z = X + Y will follow gamma distribution that is,

X+Y=Z∼gamma(2,1/1400)

2λZ∼

X+Y=Z∼gamma(2,1/1400)

2λZ∼χ2α2

The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,

P(Z≤1700)=P(1/700Z≤1.67)=

P(χ24≤1.67)=0.3614

The resultant probability is 0.3614

8 0
3 years ago
Can someone help me with this
o-na [289]

Answer:

the third option is the correct

3 0
3 years ago
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