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lesya692 [45]
3 years ago
11

Please help!!!

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

  1. b (x, x ­- 3, 0)
  2. d Infinite Solutions

Step-by-step explanation:

1. A graphing calculator or any of several solvers available on the internet can tell you the reduced row-echelon form of the augmented matrix ...

\left[\begin{array}{ccc|c}2&-2&-1&6\\-1&1&3&-3\\3&-3&2&9\end{array}\right]

is the matrix ...

\left[\begin{array}{ccc|c}1&-1&0&3\\0&0&1&0\\0&0&0&0\end{array}\right]

The first row can be interpreted as the equation ...

  x -y = 3

  x -3 = y . . . . . add y-3

The second row can be interpreted as the equation ...

  z = 0

Then the solution set is ...

  (x, y, z) = (x, x -3, 0) . . . . matches selection B

__

2. The second equation is 2 times the first equation, so the system of equations is dependent. There are infinite solutions.

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