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3 years ago

I'm stuck on this simple math problem....

Mathematics

1 answer:

Ahat [919]3 years ago

6 0

You could go down then up

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x+2=\sqrt{3x+10} 1.) What is the solution to the equation? 2.) What is the extraneous solution? Why? 3.) In general, what is an

rusak2 [61]

No entiendo nada de cómo usar esto:(

3 0

3 years ago

(repost cuz the last didn’t load) please help ‼️

shtirl [24]

1: (pi)5^2 = 78.54 then multiply that by 11 and you get 863.94
2: (pi)13^2= 530.93 then multiply that by 8 and you get 47247.44
3. (pi)18^2= 1017.88 then multiply that by 22 and you get 22393.36

8 0

3 years ago

45 points! Please help!

Tju [1.3M]

Answer:

Sequence One

Step-by-step explanation:

S = a₁ / (1 − r) is the infinite sum of a geometric series where |r| < 1.

Sequence One: r = 1/5

Sequence Two: r = 2

Sequence Three: not geometric

Sequence Four: r = -3/2

Only Sequence One has |r| < 1.

5 0

3 years ago

What is bigger 4/5 or 8/10

statuscvo [17]

They are equal because if you make 4/5 into a denominator of 10 it is 8/10

6 0

3 years ago

Read 2 more answers

A street magician asks a passerby to draw one card from a standard deck, remember it, and then replace it. The magician then shu

Romashka-Z-Leto [24]

Answer:

P( At least one of the two cards was a heart)=7/16

Step-by-step explanation:

The solution to this question can be found in two ways.

First way: Since total number of heart in a deck are four,

Probability that neither of two cards had a heart is that at both times the card drawn was not a heart, since it is an independent event, thus probability both were not heart= $\frac{3}{4}$ × $\frac{3}{4}$

= $\frac{9}{16}$

Thus, Probability that at least one of the two cards was a heart= 1- P( Neither of two cards had a heart= 1- $\frac{9}{16}$

= $\frac{7}{16}$

Second way:

Probability that first card drawn is a heart and the second one is not a heart= $\frac{1}{4}$ × $\frac{3}{4}$

= $\frac{3}{16}$

Probability that the first card drawn is not a heart and the second one is a heart= $\frac{3}{4}$ × $\frac{1}{4}$

= $\frac{3}{16}$

Probability that both cards drawn are hearts= $\frac{1}{4}$ × $\frac{1}{4}$

= $\frac{1}{16}$

Adding all these probabilities, we have the probability that at least one of the card drawn was heart= $\frac{7}{16}$

3 0

3 years ago